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yuradex [85]
3 years ago
6

What is the value 6 x 90.06

Mathematics
1 answer:
Tomtit [17]3 years ago
6 0

Answer:

540.36

Step-by-step explanation:

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Which statement describes the inverse of m(x) = x2 – 17x?
stealth61 [152]

Answer:

The correct option is;

The \ domain \ restriction \ x \geq \dfrac{17}{2} \ results \ in \ m^{-1}(x) = \dfrac{17}{2} \pm \sqrt{x + \dfrac{289}{4} }}

Step-by-step explanation:

The given information is that m(x) = x² - 17·x

The above equation can be written in the form;

y = x² - 17·x

Therefore;

0 = x² - 17·x - y

From the general solution of a quadratic equation, 0 = a·x² + b·x + c we have;

x = \dfrac{-b\pm \sqrt{b^{2}-4\cdot a\cdot c}}{2\cdot a}

By comparison to the equation,0 = x² - 17·x - y, we have;

a = 1, b = -17, and c = -y

Substituting the values of a, b and c into the formula for the general solution of a quadratic equation, we have;

x = \dfrac{-(-17)\pm \sqrt{(-17)^{2}-4\times (1) \times (-y)}}{2\times (1)} = \dfrac{17\pm \sqrt{289+4\cdot y}}{2}

Which can be simplified as follows;

x =  \dfrac{17\pm \sqrt{289+4\cdot y}}{2}= \dfrac{17}{2} \pm \dfrac{1}{2}  \times \sqrt{289+4\cdot y}} = \dfrac{17}{2} \pm \sqrt{\dfrac{289}{4} +\dfrac{4\cdot y}{4} }}

And further simplified as follows;

x = \dfrac{17}{2} \pm \sqrt{\dfrac{289}{4} +y }} = \dfrac{17}{2} \pm \sqrt{y + \dfrac{289}{4} }}

Interchanging x and y in the function of the inverse, m⁻¹(x), we have;

m^{-1}(x) = \dfrac{17}{2} \pm \sqrt{x + \dfrac{289}{4} }}

We note that the maximum or minimum point of the function, m(x) = x² - 17·x found by differentiating the function and equating the result to zero, gives;

m'(x) = 2·x - 17 = 0

x = 17/2

Similarly, the second derivative is taken to determine if the given point is a maximum or minimum point as follows;

m''(x) = 2 > 0, therefore, the point is a minimum point on the graph

Therefore, as x increases past the minimum point of 17/2, m⁻¹(x) increases to give;

The \ domain \ restriction \ x \geq \dfrac{17}{2} \ results \ in \ m^{-1}(x) = \dfrac{17}{2} \pm \sqrt{x + \dfrac{289}{4} }} to increase m⁻¹(x) above the minimum.

8 0
3 years ago
Solve for the roots in the equation below. In your final answer, include each of the necessary steps and calculations.
Nostrana [21]
x^3-27i=0
x^3=27i
x^3=27e^{i\pi/2}
x=\left(27e^{i\pi/2}\right)^{1/3}
x=3e^{i(\pi/2+2\pi k)/3}
x=3e^{i\pi(4k+1)/6}

where k\in\{0,1,2\}. This means you have

x=3e^{i\pi/6}=\dfrac32(\sqrt3+i)
x=3e^{i5\pi/6}=\dfrac32(-\sqrt3+i)
x=3e^{i9\pi/6}=-3i

as the solutions to the original equation.
4 0
3 years ago
Can someone do #1 and #2 I don't really get the answer. My teacher hasn't explain anything. He just gave us the paper and we got
Elenna [48]
1) f(x) + g(x)

= 7√x + 4 + 2√x - 2

= √x(7 + 2) + 2

= 9√x + 2  [ Final Answer ]

2) f(x) - g(x)

= 7√x + 4 - (2√x - 2)

= 7√x + 4 - 2√x + 2

= √x(7 - 2) + 6

= 5√x + 6   [ Final Answer ]

Hope this helps!
5 0
3 years ago
Select the correct answer.
anygoal [31]

Answer:

B: c(3c^2-4)

Step-by-step explanation:

1. Substitute 1 for c: (24^6-32^4)/(8^3)

2. Solve substitution: -1

3. Compare -1 to calculated answers when c=1

4. c(3c^2-4) when c=1 is -1

6 0
2 years ago
Calculate area of triangle
Radda [10]

Answer:

60cm^2

Step-by-step explanation:

15 times 8 = 120

divided by 2  = 60

3 0
3 years ago
Read 2 more answers
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