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Iteru [2.4K]
3 years ago
12

Um can someone help please and thanks

Mathematics
1 answer:
Hitman42 [59]3 years ago
3 0
You can use the pythagorean theorem
15^2 = 225
17^2 = 289
225 + b^2 = 289
b^2 = 64
b = 8

so one half of one side is 8 so the whole side would be 16

hope this helps
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Expand:<br> 4(5x+5) - 3(2x + 4)
aliina [53]

Answer:

14x + 8

Explanation:

⇒ 4(5x+5) - 3(2x + 4)

distribute inside parenthesis

⇒ 4(5x) + 4(5) - 3(2x) - 3(4)

multiply the variables

⇒ 20x + 20 - 6x - 12

collect like terms

⇒ 20x - 6x + 20 - 12

subtract like term

⇒ 14x + 8

3 0
2 years ago
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Divide 30 in the ratio of 2 : 4
cricket20 [7]
60 because 2:4 is 1/2, and when you divide by a fraction, you multiply by the reciprocal (2/1 instead of 1/2) which would be 60 in this case.
8 0
3 years ago
Find the​ (a) mean,​ (b) median,​ (c) mode, and​ (d) midrange for the data and then​ (e) answer the given question. Listed below
mafiozo [28]

Answer:

a) \bar X = 369.62

b) Median=175

c) Mode =450

With a frequency of 4

d) MidR= \frac{Max +Min}{2}= \frac{49+3000}{2}= 1524.5

<u>e)</u>s = 621.76

And we can find the limits without any outliers using two deviations from the mean and we got:

\bar X+2\sigma = 369.62 +2*621.76 = 1361

And for this case we have two values above the upper limit so then we can conclude that 1500 and 3000 are potential outliers for this case

Step-by-step explanation:

We have the following data set given:

49 70 70 70 75 75 85 95 100 125 150 150 175 184 225 225 275 350 400 450 450 450 450 1500 3000

Part a

The mean can be calculated with this formula:

\bar X = \frac{\sum_{i=1}^n X_i}{n}

Replacing we got:

\bar X = 369.62

Part b

Since the sample size is n =25 we can calculate the median from the dataset ordered on increasing way. And for this case the median would be the value in the 13th position and we got:

Median=175

Part c

The mode is the most repeated value in the sample and for this case is:

Mode =450

With a frequency of 4

Part d

The midrange for this case is defined as:

MidR= \frac{Max +Min}{2}= \frac{49+3000}{2}= 1524.5

Part e

For this case we can calculate the deviation given by:

s =\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

And replacing we got:

s = 621.76

And we can find the limits without any outliers using two deviations from the mean and we got:

\bar X+2\sigma = 369.62 +2*621.76 = 1361

And for this case we have two values above the upper limit so then we can conclude that 1500 and 3000 are potential outliers for this case

5 0
3 years ago
The point r is halfway between the intergers on the number line below and represent the number
11111nata11111 [884]

Answer:

123 456 789 10 11 12 1 3 1 4 1 5 1 5

Step-by-step explanation:

7 0
3 years ago
conor earns $9 an hour for yard work. he raked leaves one afternoon and earned $29.25. how many hours did he rake leaves? ANSWER
Assoli18 [71]

Answer:

He worked for 3.25 hours

Step-by-step explanation:

29.25 / 9 = 3.25

:D

6 0
3 years ago
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