<span>B) the bisectors of angles D, E, and F
</span>
In an inscribed circle of a triangle, all angle bisectors will pass through the center of the circle.
Pls. see attachment.
1st attachment is Triangle DEF. 2nd attachment is how inscribed circle relates to the triangle it is inscribed in.
Dudhdhhxgxgxhxdjxhhxxjdh
the answer is 8
Answer:
Choice A
Step-by-step explanation:
There should be an open circle at 0 since there is no equals in the inequality
n is greater than zero so the line goes to the right.
Choice A
Answer: 4x² + 4xy - 3y²
Concept:
When encountering questions that ask for simplifying algebraic expressions, using the FOIL method would be easier:
- <u>First</u>, which means multiplying the first terms together;
- <u>Outer</u>, which means that we multiply the outermost terms when the binomials are placed side by side;
- <u>Inner</u>, which means multiply the innermost terms together;
- <u>Last</u>, which means that we multiply the last term in each binomial together.
Solve:
<u>Given</u>
(2x - y) (2x + 3y)
<u>Expand parentheses and apply the FOIL method</u>
=4x² + 6xy - 2xy - 3y²
<u>Combine like terms</u>
=4x² + (6xy - 2xy) - 3y²
=
Hope this helps!! :)
Please let me know if you have any questions
Answer:
28
Step-by-step explanation:
The formula for trapezoid area is [(b1+b2)/2]h where the b's are the bases and the h is the height. Plugging the values in, you get 28. Have a good day!
