16 rounded to the tens place = 20
6216 rounded to the thousands place = 6000
6000/20 = 300 <==
Lets solve the question,
Given dimensions are:
Length = 26 feet
Width = 14 feet
concrete walkway with width = c
After installing the concrete walkway dimensions of the walkway will be,
Length = 26 + 2c
Width = 14 + 2c
She wants to build a wooden deck around the pool with a concrete walkway of width = w
Thus the dimensions of the wooden deck around the pool will be,
Length = 
Width = 
Now the perimeter of the wooden deck will be,
Perimeter = 2(length + width)
![= 2[(26 +2c + 2w) + 2(14 + 2c + 2w)] = 2(40 + 4c + 4w) = (80 + 8c + 8w)](https://tex.z-dn.net/?f=%3D%202%5B%2826%20%2B2c%20%2B%202w%29%20%2B%202%2814%20%2B%202c%20%2B%202w%29%5D%20%20%20%20%20%20%20%20%20%20%20%20%20%20%20%20%3D%202%2840%20%2B%204c%20%2B%204w%29%20%20%20%20%20%20%20%20%20%20%20%20%20%20%20%20%3D%20%2880%20%2B%208c%20%2B%208w%29)
Therefore, perimeter of the wooden deck would be: 80 + 8c + 8w
Perimeter = (80 + 8c + 8w)
Learn more about Perimeter on:
brainly.com/question/397857
#SPJ10
Answer: 145
Step-by-step explanation: I say this because it has 14. 4 then
Answer:
2.5
×
t
=
2.5
t
Step-by-step explanation:
Answer:
The probability that a household has at least one of these appliances is 0.95
Step-by-step explanation:
Percentage of households having radios P(R) = 75% = 0.75
Percentage of households having electric irons P(I) = 65% = 0.65
Percentage of households having electric toasters P(T) = 55% = 0.55
Percentage of household having iron and radio P(I∩R) = 50% = 0.5
Percentage of household having radios and toasters P(R∩T) = 40% = 0.40
Percentage of household having iron and toasters P(I∩T) = 30% = 0.30
Percentage of household having all three P(I∩R∩T) = 20% = 0.20
Probability of households having at least one of the appliance can be calculated using the rule:
P(at least one of the three) = P(R) +P(I) + P(T) - P(I∩R) - P(R∩T) - P(I∩T) + P(I∩R∩T)
P(at least one of the three)=0.75 + 0.65 + 0.55 - 0.50 - 0.40 - 0.30 + 0.20 P(at least one of the three) = 0.95
The probability that a household has at least one of these appliances is 0.95