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grin007 [14]
3 years ago
8

(AAAA HELP PLS XD WILL MARK BRAINLIEST) Nhia is setting up a marble tournament for the kids in her

Mathematics
1 answer:
aksik [14]3 years ago
4 0

Given that we have 47 kids and each kid needs 10 marbles, find out how many bags of 24 marbles will we need.

First, we will multiply 47 by 10 to get the amount of marbles needed.

47 x 10 = 470

So, that means we need 470 marbles in total.

Then, we divide 470 by 24 to see how many bags of 24 marbles 470 marbles is.

470 / 24 = 19.5833

Since, we can't have 19.5833 bags, we have to check what it would be if we only used 19.

19 x 24 = 456

470 - 456 = 14

Since, 18 is the closest number of bags but it has less than 470 it would not be correct.

Therefore, the best answer would be B. 25 since it is better to have extra marbles but not a very wide margin.

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So I have this question here, can someone please help me?
salantis [7]

Answer:

Use tan trig ratio:

\sf tan(\theta)=\dfrac{O}{A}

where \theta is the angle, O is the side opposite the angle, and A is the side adjacent the angle

Given:

  • \theta = 39°
  • O = 10
  • x = A

Substituting these values into the formula:

\implies  \tan(39)=\dfrac{10}{x}

Multiplying both sides by x:

\implies  x\tan(39)=10

Dividing both sides by \tan(39) :

\implies  x=\dfrac{10}{\tan(39)}

\implies  x=12.34897157...

\implies  x=12.3 \ \textsf{(nearest tenth)}

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A trapezoid has only one pair of parallel sides (the first one)

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There are 17 families, each of the family has boys and girls. Write two equations that will give the total number of children.
Elodia [21]

Answer:

Step-by-step explanation:

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3 years ago
Work out the value of 1. 7/2 -a ² 2. 3x-8 = 19
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Can someone help me with one pleaseT (ToT)
uysha [10]

Answer:

Add 1 to both sides.

Multiply both sides by -2.

Add 8 to both sides.

Divide both sides by 5.

Step-by-step explanation:

<u>Step 1</u>

-\dfrac{1}{2}(5x-8)-1=6\quad \quad \textsf{Write the equation.}

<u>Step 2</u>

-\dfrac{1}{2}(5x-8)=7 \quad \quad \textsf{Add 1 to both sides.}

This is called the <u>Addition Property of Equality</u>.  When the same number is added to both sides of an equation, the two sides remain equal.

\implies -\dfrac{1}{2}(5x-8)-1+1=6+1

\implies -\dfrac{1}{2}(5x-8)=7

<u>Step 3</u>

5x-8=-14 \quad \quad \textsf{Multiply both sides by -2.}

This is called the <u>Multiplication Property of Equality</u>.  When both sides of an equation are multiplied by the same number, the two sides remain equal.

\implies -2 \cdot -\dfrac{1}{2}(5x-8)=-2 \cdot 7

\implies 5x-8=-14

<u>Step 4</u>

5x=-6 \quad \quad \textsf{Add 8 to both sides.}

This is called the <u>Addition Property of Equality</u>.  When the same number is added to both sides of an equation, the two sides remain equal.

\implies 5x-8+8=-14+8

\implies 5x=-6

<u>Step 5</u>

x=-\dfrac{6}{5} \quad \quad \textsf{Divide both sides by 5.}

This is called the <u>Division Property of Equality</u>.  When both sides of an equation are divided by the same number, the two sides remain equal.

\implies \dfrac{5x}{5}=\dfrac{-6}{5}

\implies x=\dfrac{-6}{5}

<u>Conclusion</u>

<u></u>

<u />\begin{aligned}-\dfrac{1}{2}(5x-8)-1 & =6 & \quad \quad& \textsf{Write the equation.}\\\\-\dfrac{1}{2}(5x-8) & =7 & & \boxed{\textsf{Add 1 to both sides.}}\\\\5x-8 & =-14 & & \boxed{\textsf{Multiply both sides by -2.}}\\\\5x & =-6 & & \boxed{\textsf{Add 8 to both sides.}}\\\\x & =-\dfrac{6}{5} & & \boxed{\textsf{Divide both sides by 5.}}\\\end{aligned}

Learn more about Property Laws here:

brainly.com/question/28255621

brainly.com/question/28210762

5 0
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