the answer is, 14666074545975
3/8 0f 100
100 / 8 = 12.5
Now, let's multiply this by 3 to be able to get the value
=> 12.5 * 3 = 37.5 is the value of 3/8 of 100.
This is a mixed number because its a combination of whole and decimal numbers.
The answer will be 21u^6v^8
For this case, what you should do is calculate the surface area of the figure.
We have then:
Triangles:
A1 = (1/2) * (7) * (12)
A1 = 42 in ^ 2
Rectangles:
A2 = (1) * (12.5)
A2 = 12.5 in ^ 2
A3 = (1) * (7)
A3 = 7 in ^ 2
Finally, the total surface area is:
A = 2A1 + 2A2 + A3
Substituting values:
A = 2 (42) + 2 (12.5) + (7)
A = 84 + 25 + 7
A = 116 in ^ 2
Answer:
the amount of cardboard needed to make a box for a single slice of pizza is:
A = 116 in ^ 2
so, we have two 54x18 rectangles, so their perimeter is simply all those units added together, 54+54+54+54+18+18+18+18 = 288.
we know the circle's diameter is 1.5 times the width, well, the width is 18, so the diameter of the circle must be 1.5*18 = 27.
![\bf \stackrel{\textit{circumference of a circle}}{C=d\pi }~~ \begin{cases} d=diameter\\[-0.5em] \hrulefill\\ d=27 \end{cases}\implies C=27\pi \implies C=\stackrel{\pi =3.14}{84.78} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{perimeter of the rectangles}}{288}~~~~+~~~~\stackrel{\textit{perimeter of the circle}}{84.78}~~~~=~~~~372.78](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7B%5Ctextit%7Bcircumference%20of%20a%20circle%7D%7D%7BC%3Dd%5Cpi%20%7D~~%20%5Cbegin%7Bcases%7D%20d%3Ddiameter%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20d%3D27%20%5Cend%7Bcases%7D%5Cimplies%20C%3D27%5Cpi%20%5Cimplies%20C%3D%5Cstackrel%7B%5Cpi%20%3D3.14%7D%7B84.78%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7Bperimeter%20of%20the%20rectangles%7D%7D%7B288%7D~~~~%2B~~~~%5Cstackrel%7B%5Ctextit%7Bperimeter%20of%20the%20circle%7D%7D%7B84.78%7D~~~~%3D~~~~372.78)
