Answer:
B. No because the sample is not representative of the population.
Step-by-step explanation:
If in the exact population, there is more females than males, then that sould also be represented in the sample population for it to be accurate.
Answer:
T = 40 (minutes?)
Step-by-step explanation:
Given the equation G = 50 + 20T, where G = the total amount of gas and T = the amount of Time, we know that there is already 50 gallons of gas in the tank and that the rate at which it is pumped is 20 gallons per minute (I am assuming, though it is not stated in the problem). Given that the tank holds 850 gallons, we can plug in the values into the equation and solve for the missing variable, T:
850 = 50 + 2T
Subtract 50 from both sides: 850 - 50 = 50 + 2T - 50 or 800 = 2T
Divide 2 from both sides: 800/2 = 2T/2
Solve for T: 40 = T
Answer:
i think c. because it will affect your rights as a citizen for those "taxes" Not checks and balances because it won't affect that because you will still get your checks for work and stuff. Know what i mean?
If correct, please mark brainliest! :)
If we apply the distributive law to right side of the third choice we get:-
-12x - 9 = -9 - 12x
right side = left side so infinite solutions
1) gradient of line = Δ y ÷ Δ x
= (5 -2) ÷ (3 - (-6))
= ¹/₃
using the point-slope form (y-y₁) = m(x-x₁)
using (3,5)
(y - 5) = ¹/₃ (x -3)
y - 5 = ¹/₃x - 1
⇒ <span> y = ¹/₃ x + 4 [OPTION D]
</span>2) y = 2x + 5 .... (1)
<span> </span>y = ¹/₂ x + 6 .... (2)
by substituting y in (1) for y in (2)
2x + 5 = ¹/₂ x + 6
³/₂ x = 1
x = ²/₃
by substituting found x (2)
y = ¹/₂ (²/₃) + 6
y = ¹⁹/₃
∴ common point is (²/₃ , ¹⁹/₃) thus answer is FALSE [OPTION B]
3) Yes [OPTION A]
This is because the both have a gradient of 5 and if they have the same gradient then that means that the two lines are parallel to each other.
4) No [OPTION B]
Two lines are perpendicular if their gradients multiply to give - 1 and as such one is the negative reciprocal of the other. Since both gradients are ¹/₂ then they are actually parallel and not perpendicular.