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chubhunter [2.5K]
3 years ago
15

Find the coefficient of the t4 term in the expansion of (4t– 3)^5

Mathematics
1 answer:
Sauron [17]3 years ago
5 0

Answer:

-4320t^2

Step-by-step explanation:

Use Pascal's triangle to figure out the variables.

In the 5th expansion, we see that the 4th term is:

10x^2 y^3

Plug in the values,

10*(4)^2 * (-3)^3 = -4230.

However, since the -3 in the original expression does not have a variable next to it, we do not include it in our answer.

Therefore, the 4th term is -4230t^2

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Daniel [21]

A. 8^9/2= around 11585.2375; (sqrt8)^9= around 11585.2375. So choice A shows a pair of equivalent expressions.

B. (3sqrt125)^9=1,953,125; 125^9/3=1,953,125. So choice B also shows a pair of equivalent expressions.

C. 12^2/7= around 2.03394; (sqrt12)^7= around 5,985.96759. So choice C does not show a pair of equivalent expressions.

D. 4^1/5=around 1.31951; (sqrt4)^5=32. So choice D also doesn't show a pair of equivalent expressions.

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Answer:

$88

Step-by-step explanation:

first, you find 20% of 57 which = 11.4

then subract it with 57 which looks like 57-11.4 = 45.6

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then you add them both  which = 45.6+ 42.4= 88

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