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Maurinko [17]
3 years ago
11

12. The following represents two substances by showing only one molecule 1 point

Chemistry
1 answer:
mars1129 [50]3 years ago
7 0

Answer:

b

Explanation:

etbhte4bt4ebhgetbv

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Glaxo Smith Kline (GSK) in Research Triangle Park has hired a recent biology graduate to explore a drug that would inactive memb
Rainbow [258]

Answer:

Glucose would not be able to get into the cell treated with this chemical

Potassium mwill not be able to move or transport may be affected

Explanation:

As all membrane transport proteins are inactivated glucose is abig molecule it cannot pass without transporter protein.

Potassium transport is through sodium potassium pump and leak channels. As all transport protein are affected so it should not be able to move but if drug does not affect them then they will be unaffected.

4 0
4 years ago
Predict the type of bonding in each of the following substances. Provide their chemical
Akimi4 [234]
O2 is water.
But the Wannsee and answer is c
6 0
3 years ago
why would you expect to see similar rocks and rock structures on two land masses that were connected at one time?
tangare [24]
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3 0
3 years ago
Below is a proposed mechanism for the decomposition of H2O2. H2O2 + I– → H2O + IO– slow H2O2 + IO– → H2O + O2 + I– fast Which of
Savatey [412]

Answer: Option (d) is the correct answer.

Explanation:

The given equations as as follows.

       H_{2}O_{2} + I^{-} \rightarrow H_{2}O + IO^{-}           (slow)

       H_{2}O_{2} + IO^{-} \rightarrow H_{2}O + O_{2} + I^{-}

Therefore, overall reaction equation will be as follows.

     2H_{2}O_{2} + I^{-} + IO^{-} \rightarrow 2H_{2}O + O_{2} + IO^{-} + I^{-}

So, cancelling the spectator ions then the equation will be as follows.

         H_{2}O_{2} \rightarrow 2H_{2}O + O_{2}

As, it is known that slow step of a reaction is the rate determining step. Therefore, rate law for the slow step will be as follows.

        H_{2}O_{2} + I^{-} \rightarrow H_{2}O + IO^{-}

                 Rate law = k[H_{2}O_{2}][I^{-}]

Hence, the reaction is first order with respect to [I^{-}] and it is also first order reaction with respect to [H_{2}O_{2}].

Also, [I^{-}] acts as a catalyst in the reaction.

Thus, we can conclude that the incorrect statement is IO^{-} is a catalyst.

6 0
3 years ago
The half reaction of an oxidation-reduction shows that iron gains electrons. What does this electron gain mean or iron?
ale4655 [162]

Answer:

C. its reduced

Explanation:

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