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Ber [7]
3 years ago
10

Glaxo Smith Kline (GSK) in Research Triangle Park has hired a recent biology graduate to explore a drug that would inactive memb

rane transport proteins in the plasma membrane. The recent graduate discovered a chemical that inactivated all membrane transport proteins. Wich of the following molecule(s) would not be able to get into a cell treated with this chemical?
a. testosterone
b. CO2
c. K+
d. glucose
Chemistry
1 answer:
Rainbow [258]3 years ago
4 0

Answer:

Glucose would not be able to get into the cell treated with this chemical

Potassium mwill not be able to move or transport may be affected

Explanation:

As all membrane transport proteins are inactivated glucose is abig molecule it cannot pass without transporter protein.

Potassium transport is through sodium potassium pump and leak channels. As all transport protein are affected so it should not be able to move but if drug does not affect them then they will be unaffected.

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Given a fixed amount of gas held at constant pressure, calculate the volume it would occupy if a 2.00 L sample were cooled from
aliina [53]

Answer:

1.82 L

Explanation:

We are given the following information;

  • Initial volume as 2.0 L
  • Initial temperature as 60.0°C
  • New volume as 30.0 °C

We are required to determine the new volume;

From Charles's law;

\frac{V_1}{T_1}=\frac{V_2}{T_2}

Where, V_1 and V_2 are initial and new volume respectively, while T_1 and T_2 are initial and new temperatures respectively;

T_1= 333 K

T_2=303K

V_1 =2.0L

Rearranging the formula;

V_2=\frac{V_1T_2}{T_1}

    = \frac{(2.0L)(303K)}{333K} \\=1.820 L

Therefore, the new volume that would be occupied by the gas is 1.82 L

7 0
3 years ago
A farmer selectively breeds tomatoes to be shipped to grocery stores across the United States. Which of the following genetic tr
Studentka2010 [4]

Answer:

D

Explanation:

It would definitely affect size because breeding will change that trait

5 0
3 years ago
Gaseous ethane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 9.32 g of ethane is
Pie

Answer:

There will remain 8.06 grams of ethane

Explanation:

Step 1: Data given

Mass of ethane = 9.32 grams

Mass of oxygen = 12.0 grams

Molar mass ethane = 30.07 g/mol

Molar mass oxygen = 32.00 g/mol

Step 2: The balanced equation

2 C2H6 + 7 O2 → 4 CO2 + 6 H2O

Step 3: Calculate moles ethane

Moles ethane = mass ethane / molar mass ethane

Moles ethane = 9.32 grams / 30.07 g/mol

Moles ethane = 0.3099 moles

Step 4: Calculate moles oxygen

Moles oxygen = 12.0 grams / 32.0 g/mol

Moles oxygen = 0.375 moles

Step 5: Calculate the limiting reactant

For 2 moles ethane we need 7 moles O2 to produce 4 moles CO2 and 6 moles H2O

O2 is the limiting reactant. It will completely be consumed ( 0.375 moles)

Ethane is in excess. There will react 2/7 * 0.375 = 0.107 moles

There will remain 0.375 - 0.107 = 0.268 moles

Step 6: Calculate mass ethane

Mass ethane = moles ethane * molar mass ethane

Mass ethane = 0.268 moles * 30.07 g/mol

Mass ethane = 8.06 grams

There will remain 8.06 grams of ethane

7 0
3 years ago
Review this balanced neutralization reaction: HBr + KOH KBr + H2O. Which substance is the base?
Olegator [25]
B KOH
I would say this is the base for the compound substance
8 0
3 years ago
Select the molecule where free rotation around one or more bonds is not possible. Group of answer choices N2H4 C2Cl4 NH3 C2H6 CC
Alexandra [31]

Answer:

C₂Cl₄

Explanation:

To know if free rotation around a bond in a compound is possible, we need to see the structure of the compound (picture in attachment).

In single bonds, which are formed by σ bonds, the atoms are not fixed in a single position, and free rotation is permitted.

Double and triple bonds are formed by a σ bond and one or two π bonds, respectively. These bonds do not allow rotation, since it is not possible to twist the ends without breaking the π bond.

The chloroethylene (C₂Cl₄) has two carbons with an sp2-sp2 hybridization, they are bonded together by a double bond. <u>Free rotation on this bond is not possible, because six atoms, including the carbon atoms, doubly bonded and the four chlorine atoms bonded to them, must be on the same plane. </u>

4 0
3 years ago
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