In cellular biology, active transport is the movement of molecules across a membrane from a region of their lower concentration to a region of their higher concentration—against the concentration gradient. Active transport requires cellular energy to achieve this movement. There are two types of active transport: primary active transport that uses ATP, and secondary active transport that uses an electrochemical gradient. An example of active transport in human physiology is the uptake of glucose in the intestines.
Answer :
A = In
B = 27
C = 73
D = 49
E = 56
F = 54
G = 66
H = 108
I = 32
Explanation :
Atomic number is defined as the number of protons or number of electrons.
Atomic number = number of protons = number of electrons
Mass number is defined as the sum of number of protons and number of neutrons.
Number of neutrons = Mass number - Number of protons
Number of electrons = Number of protons - charge
Element Number of Number of Number of Atomic
symbol protons electrons neutrons mass
Co 27 27 31 58
In 49 49 66 115
Ta 73 73 108 181
Ba²⁺ 56 54 81 137
S²⁻ 16 18 16 32
Pressure since pressure is defined as force per unit area and the molecules exert a force on the walls of the container when they bombard it
Answer:
![Hg^0+2OH^-\rightarrow Hg^{2+}O+H_2O+2e^-](https://tex.z-dn.net/?f=Hg%5E0%2B2OH%5E-%5Crightarrow%20Hg%5E%7B2%2B%7DO%2BH_2O%2B2e%5E-)
Explanation:
Hello,
In this case, mercury (II) oxide (HgO) is obtained via the reaction:
![Hg(l)+O_2\rightarrow HgO](https://tex.z-dn.net/?f=Hg%28l%29%2BO_2%5Crightarrow%20HgO)
Nonetheless, since it is a reaction carried out in basic solution, mercury's half-reaction only, must be:
![Hg^0+2OH^-\rightarrow Hg^{2+}O+H_2O+2e^-](https://tex.z-dn.net/?f=Hg%5E0%2B2OH%5E-%5Crightarrow%20Hg%5E%7B2%2B%7DO%2BH_2O%2B2e%5E-)
Thus, it is seen that OH ionis should be added due to the basic aqueous solution considering that 2 electrons are transferred from 0 to 2 in mercury.
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Answer:
Maximum number of moles of AlCl3 produced is 5 moles
Explanation:
First thing's first, let's bring out the balanced chemical equation.
2Al + 3Cl2 -> 2AlCl3
Before proceeding to calculating the maximum number of moles of AlCl3 that can be formed, we have to identify the limiting reagent.
Every 2 mole of AlCl3 requires 2 moles of Al and 3 moles of Cl2.
If all of the 5 moles of Al were to be used up, there would need to be 5 × (2 / 3) or 3.333 moles of Cl2. 6 moles of Cl2 is available, this means Al is our limiting reagent.
5 mol of Al * (2 mol of Cl2 / 3 mol of Al) = 3.33 mol of Cl2
From the equation, 2 mol of Al produces 2 mol of AlCl3. This means 5 mol of Al would produce x?
2 = 2
5 = x
x = (5 * 2 ) / 2
x = 10 /2 = 5
Maximum number of moles of AlCl3 produced is 5 moles