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Paul [167]
3 years ago
15

(Grade6math) Can somebody plz answer these questions correct in simplify form.. cuz idk how to answer it like that..still learni

ng.
WILL MARK BRAINLIEST!!!!!

Mathematics
1 answer:
babunello [35]3 years ago
6 0

Answer:

1. 1, 2. -15, 3. -18, 4. -1, 5. -11. 6. 22

Step-by-step explanation:

REMEMBER: If a positive multiplies a negative, it will result in a negative. If a negative multiplies a negative, it will resolve as a positive

1. 7 - 2 x 3 = 1

First, multiply 2 and 3 to get 6

7 - 6

Subtract the numbers to get 1

2. -8 + 14 / (-2) = -15

First, do 14 divided by -2 to get -7

-8 + -7

Add the two numbers to get -15

3. -6 + (-3) x 4 = -18

First, multiply -3 and 4 to get -12

-6 + -12

Add the two numbers together to get -18

4. 48 / (-12) +3 = -1

Divide 48 and -12 to get -4

-4 + 3

Add the two numbers to get -1

5. 16 / (-2) -3 = -11

Divide 16 by -2 to get -8

-8 - 3 = -8 + (-3)

Add the two numbers together to get -11

6. -11 x 4 / (-2) = 22

Work the problem from left to right, start with -11 x 4 to get -44

-44 / -2

Divide the equation to get 22

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A company employs two shifts of workers. Each shift produces a type of gasket where the thickness is the critical dimension. The
Oksanka [162]

Answer:

a) [-0.134,0.034]

b) We are uncertain

c) It will change significantly

Step-by-step explanation:

a) Since the variances are unknown, we use the t-test with 95% confidence interval, that is the significance level = 1-0.05 = 0.025.

Since we assume that the variances are equal, we use the pooled variance given as

s_p^2 = \frac{ (n_1 -1)s_1^2 + (n_2-1)s_2^2}{n_1+n_2-2},

where n_1 = 40, n_2 = 30, s_1 = 0.16, s_2 = 0.19.

The mean difference \mu_1 - \mu_2 = 10.85 - 10.90 = -0.05.

The confidence interval is

(\mu_1 - \mu_2) \pm t_{n_1+n_2-2,\alpha/2} \sqrt{\frac{s_p^2}{n_1} + \frac{s_p^2}{n_2}} = (-0.05) \pm t_{68,0.025} \sqrt{\frac{0.03}{40} + \frac{0.03}{30}}

= -0.05\pm 1.995 \times 0.042 = -0.05 \pm 0.084 = [-0.134,0.034]

b) With 95% confidence, we can say that it is possible that the gaskets from shift 2 are, on average, wider than the gaskets from shift 1, because the mean difference extends to the negative interval or that the gaskets from shift 1 are wider, because the confidence interval extends to the positive interval.

c) Increasing the sample sizes results in a smaller margin of error, which gives us a narrower confidence interval, thus giving us a good idea of what the true mean difference is.

6 0
4 years ago
There are three numbers for the combination to the store’s safe. The first number is 17. The other two numbers can be multiplied
dlinn [17]

Answer:

Step-by-step explanation:

7 0
3 years ago
Try to sketch by hand the curve of intersection of the parabolic cylinder y = x2 and the top half of the ellipsoid x2 + 7y2 + 7z
vovikov84 [41]

Plug y=x^2 into the equation of the ellipsoid:

x^2+7(x^2)^2+7z^2=49

Complete the square:

7x^4+x^2=7\left(x^4+\dfrac{x^2}7+\dfrac1{14^2}-\dfrac1{14^2}\right)=7\left(x^2+\dfrac1{14}\right)^2+\dfrac1{28}

Then the intersection is such that

7\left(x^2+\dfrac1{14}\right)^2+7z^2=\dfrac{1371}{28}

\left(x^2+\dfrac1{14}\right)^2+z^2=\dfrac{1371}{196}

which resembles the equation of a circle, and suggests a parameterization is polar-like coordinates. Let

x(t)^2+\dfrac1{14}=\sqrt{\dfrac{1371}{196}}\cos t\implies x(t)=\pm\sqrt{\sqrt{\dfrac{1371}{196}}\cos t-\dfrac1{14}}

y(t)=x(t)^2=\sqrt{\dfrac{1371}{196}}\cos t-\dfrac1{14}

z=\sqrt{\dfrac{1371}{196}}\sin t

(Attached is a plot of the two surfaces and the intersection; red for the positive root x(t), blue for the negative)

4 0
3 years ago
Evaluate 3x-2y; if x=7 and y=3
Zarrin [17]

Answer:

15

Step-by-step explanation:

3x - 2y = ?

3(7) - 2(3) = ?

21 - 6 = ?

= 15

All you have to do is substitute the given values & follow the order of operations! Best of luck.

3 0
3 years ago
Which of the following are equivalent to 160%
vichka [17]
18/10
9/5
Anything along those lines!
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3 years ago
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