Answer:
12
Step-by-step explanation:
There are 4 different digits to choose from. Since we want 2-digit number, we will see what digits can we put in place of 1st digit and what digit can we place in place of 2nd digit.
Hence, <u><em>how many digits (from 1,5,6 and 8) can be placed in the 1st digit of the number we want?</em></u>
Any one of the four digits (1,5,6, or 8).
Now, <em><u>How many digits (from 1,5,6 and 8) can be placed as the 2nd digit of the number we want?</u></em>
Any one of the THREE digits (since repetition is not allowed, we disregard the initial digit).
Thus the number of two-digit positive integers is 4 * 3 = 12
The answer simplified is 49y^8
It should be noted that No. the value of the 9 in the hundred place is not ten times the value of 3 in the tens place.
<h3>How to illustrate the information?</h3>
It should be noted that the value of 3 in 1934 is 30 and the value of 9 is 900.
1934 = 1000 + 900 + 30 + 4
Therefore the value of 9 will be:
= 30 × 3
Therefore, the the value of the 9 in the hundred place is 30 times the value of 3 in the tens place.
Learn more about place values on:
brainly.com/question/2041524
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How are you? Ok so It probably B but I’m not sure so just wait a few minutes till someone else answers because I’m not sure
We know a or b != 0
but a-b==0 so both are the same unknown number
b/a must = 1
so
a/b is equivalent to b/a as a/b=1 as well.
So the last answer choice.
