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Nataly_w [17]
3 years ago
6

7 in.

Mathematics
1 answer:
fgiga [73]3 years ago
6 0
258 cubic inches

Since the boxes are kind of on their own—>
First box: 7*2*12 = 168
Second box: 5*2*9=90
168+90 = 258
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Find the area of the rug. DO NOT ROUND. <br><br> what is the area?
Neporo4naja [7]

Answer:

28.26 ft²

Explanation:

\sf area \ of  \ circle    = \pi r^2

<u>Here given diameter: 6 ft</u>

radius: d/2 = 6/2 = 3 ft

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area of rug:

\dashrightarrow \  \pi (3)^2

\dashrightarrow \  9\pi

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The 8 in 782 is in the tens value.

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Alinara [238K]

5 times the product of x and y = 5xy

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The following data represent the pulse rates? (beats per? minute) of nine students enrolled in a statistics course. Treat the ni
aleksandr82 [10.1K]

Answer:

a) population\hspace{0.1cm} mean = \frac{64 + 77 + 89 + 69 + 89 + 65 + 88 + 69 + 87}{9} = 77.44

b)sample\hspace{0.1cm} mean 1 = \frac{65 + 69 + 77}{3} = 70.3

   sample\hspace{0.1cm} mean 2 = \frac{64 + 69 + 77}{3} = 70

c) both the means of the two samples underestimate the population mean.

   the mean pulse rate of sample 1 underestimates the population mean.

   the mean pulse rate of sample 2 underestimates the population mean.

Step-by-step explanation:

i) population size, N = 9

a) population\hspace{0.1cm} mean = \frac{64 + 77 + 89 + 69 + 89 + 65 + 88 + 69 + 87}{9} = 77.44

b)sample\hspace{0.1cm} mean 1 = \frac{65 + 69 + 77}{3} = 70.3

   sample\hspace{0.1cm} mean 2 = \frac{64 + 69 + 77}{3} = 70

c) both the means of the two samples underestimate the population mean.

   the mean pulse rate of sample 1 underestimates the population mean.

   the mean pulse rate of sample 2 underestimates the population mean.

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3 years ago
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kiruha [24]

Step 1

The property of a parallelogram is that diagonals of a parallelogram bisect each other and hence have the same midpoint.

This means that the diagonals cut themselves into two equal halves.

Hence, they must have the same mid-points.

Therefore, if we prove that AC and BD have the same midpoint, then ABCD is a parallelogram.

Step 2

Find the midpoint of BD and AC

\begin{gathered} (\frac{x_2+x_1}{2}),(\frac{y_2+y_1}{2}) \\ BD=(-\frac{1}{2},\frac{9}{2}) \\ AC=(-\frac{1}{2},\frac{9}{2}) \end{gathered}

Since they have the same midpoint, the answer will be;

We Prove that AC and BD have the same midpoint which we have done. we know the diagonals of a parallelogram bisect each other; therefore, they have the same midpoint and ABCD is a parallelogram.

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1 year ago
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