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atroni [7]
3 years ago
15

Determine whether the situation is linear or nonlinear, and proportional or nonproportional

Mathematics
1 answer:
Arlecino [84]3 years ago
6 0

Answer:

  linear and non-proportional

Step-by-step explanation:

When the same amount is added each week, the relationship is linear. When the initial value is 50, not zero, the relationship is non-proportional.

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What is 2x-(x-2)=-2-(x-1)​
bezimeni [28]
Distribute first so
2x-x+2=2-x+1
Combine like terms so
x+2=3-x
Get terms on the same side so
2x+2=3
Subtract 2
2x=1
Divide
X=1/2 or .5

8 0
3 years ago
Janie receives an allowance of $3 per week.
inn [45]
Janie receives an allowance of $3 per week.
In addition, she can earn $2 for each chore she does.
This week, she wants to earn enough money to buy a CD for $13.
Janie can do fractions of chores.

Write an inequality to determine the number of chores Janie must do this week to earn enough money to buy a CD.
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8 0
3 years ago
Read 2 more answers
What are the excluded values of x for
ss7ja [257]

Answer:

x = - 2, x = 9

Step-by-step explanation:

Given

f(x) = \frac{x^2-9x}{x^2-7x-18}

The denominator of f(x) cannot be zero as this would make f(x) undefined.

Equating the denominator to zero and solving gives the values that x cannot be.

x² - 7x - 18 = 0

(x - 9)(x + 2) = 0

Equate each factor to zero and solve for x

x + 2 = 0 ⇒ x = - 2

x - 9 = 0 ⇒ x = 9

The excluded values are x = - 2, x = 9

3 0
3 years ago
Please help on this equation I don't get it.
olasank [31]

Answer:

0.6 liters

Step-by-step explanation:

3 liters divided amongst 5 people comes to 0.6 liters per person. there are approximately 33.8 ounces in a liter so in ounces, everyone would get approximately 56.35 ounces of soda.

for a picture you could draw a cup with soda in it and label it to show the amount

7 0
3 years ago
What’s the probability of getting 6 or more girls from 8 births?
Lemur [1.5K]

Answer:

3/4 or 6/8

Step-by-step explanation:

6/8 when simplified is 3/4. That is the probability over the total.

8 0
3 years ago
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