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Kobotan [32]
2 years ago
8

If you drew a vertical line every time the SIN graph touched the x-axis, what function would that create an asymptote for?

Mathematics
1 answer:
Gnoma [55]2 years ago
8 0

Answer:symptotes are invisible lines which are graphed function will approach very closely but not ever touch. This lesson covers vertical and horizontal

Step-by-step explanation: :)

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The length, l, of a rectangle is 6/5 its width, w.the length, l, of the rectangle is 12 inches. what is the perimeter of the rec
DerKrebs [107]
W= 6/5L   L=12 inches
W=14.4 inches
perimeter of rectangle = 2(W+L)
                                       =2(14.4+12)
                                       =2(26.4)
                                       =52.8 inches

8 0
3 years ago
In the trapezoid at the right, BE= 2x-8, DE= x-4, and AC= x+2
Marta_Voda [28]

Answer:

A.  x = 5 (Equation below)

B. AC = 9 | BD = 9

Step-by-step explanation:

A. Since we know the diagonals of an isosceles trapezoid are congruent, we know that the two bottom parts of the diagonal BD (2x - 8 and x - 4) are congruent to the diagonal AC (x + 2) . This means you can just equal them together and get the value of x:

2x - 8 + x - 4 = x + 2

3x - 12 = x + 2

3x = x + 14

2x = 14

x = 7

B. Just plug in 5 for x:

AC = x + 2 = 7 + 2 = 9

BD = 2x - 8 + x -4 = 3x - 12 = 21 - 12 = 9

5 0
3 years ago
What force would be required to accelerate a 1,100 kg car to 0.5m/s?
ira [324]

Answer:

550 N

Step-by-step explanation:

We can solve the problem by using Newton's second law:

F=ma

F is the force required to accelerate the car

m is the mass of the car

a is the acceleration of the car

In this problem, the mass is m=1100 kg, while the acceleration is a=0.5 m/s^2, therefore the force required to accelerate the car is

F=ma=(1100kg)(0.5m/s^{2} )=550N

Hope this helps!

3 0
3 years ago
What is the simplest form of the expression?
Rina8888 [55]
^ 3 sqrt 750 + ^ 3 sqrt 2058 - ^ 3 sqrt 48
 Rewriting the expression we have
 ^ 3 sqrt (6 * x ^ 3) + ^ 3 sqrt (6 * y ^ 3) - ^ 3 sqrt (6 * z ^ 3)
 That is, we have the following equations:
 6 * x ^ 3 = 750
 6 * y ^ 3 = 2058
 6 * z ^ 3 = 48
 Clearing x, y and z we have:
 x = 5
 y = 7
 z = 2
 Then, rewriting the expression
 x (^ 3 sqrt (6)) + y (^ 3 sqrt (6)) - z (^ 3 sqrt (6))
 Substituting the values
 5 (^ 3 sqrt (6)) + 7 (^ 3 sqrt (6 *)) - 2 (^ 3 sqrt (6))
 10 (^ 3 sqrt (6))
 answer
 the simple form of the expression is
 D) 10 ^ 3 sqrt 6
3 0
4 years ago
I will give brainliest to the person who answers all questions
stellarik [79]

Answer: Hope this helps!

Left to right - Q1 - Q5

1,500, 1,250, 0.25, 105, 25%

Step-by-step explanation:

Q1 - 15,000 * 0.02 * 5 = 1,500

Q2 - 25,000 * 0.01 * 5 = 1,250

Q3 - 20 - ((6 * 1) + (3 * 0.75) + (10 * 0.35) + (4 * 2)) = 0.25, 25 cents

Q4 - 30x + 1,000 = 4,200 (X = 107) Approximately 105 jobs

Q5 - 1,584 / (32 * 66) = 0.75 (75%) 100% - 75% = 25%

4 0
2 years ago
Read 2 more answers
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