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Anastaziya [24]
3 years ago
6

Express the distance traveled as a function of the number of hours at the average speed. The morris family is traveling from pro

vidence to Fredericksburg. Given city traffic they will average 45 mph
Mathematics
1 answer:
shusha [124]3 years ago
6 0

Answer:

Dist = 45 m/h * x h

Step-by-step explanation:

We know a speed is a measure of distance over time:  speed = dist / time

In this case, we are looking for a distance expressed in terms of time.

So, we only need to modify the formula a bit: dist = speed * time

We don't know the time (which will be a variable), but we know their speed.  So, the formula becomes:

Dist = 45 m/h * x h

Enter the number of hours in the formula and that will give you an approximation of the distance traveled within that time (approximation since our result will be rely on an average).

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Help me with this plssss I dont understand ​
frozen [14]

Answer:

y = 18

a = -2

Step-by-step explanation:

Hello There!

For the first one we need to create an equation to solve for y

23+7=y+12

30=y+12

isolate the variable using inverse operations

subtract 12 from each side

30-12=18

we're left with y = 18

for the second one we need to create an equation to solve for a

3+15+a=8+8+8

3+15=18

8+8+8=16

16=18+a

step 1 subtract each side by 18

16-18=-2

we're left with a = -2

8 0
3 years ago
Read 2 more answers
Can some one help with domain and range
shusha [124]
Yeah whats the question
6 0
3 years ago
Let U = {q, r, s, t, u, v, w, x, y, z}
Sliva [168]

The Set A’∪ B =  { r, t, v, x, z, q, s, y, z }

We have the following sets -

U = {q, r, s, t, u, v, w, x, y, z}

A = {q, s, u, w, y}

B = {q, s, y, z}

C = {v, w, x, y, z}

We have to determine the set represented by -  A' ∪ B.

<h3>What is a Set?</h3>

A set is a collection of elements or numbers or objects, represented within the curly brackets { }. For example: {1,2,3,4} is a set of numbers.

According to question, we have -

U = {q, r, s, t, u, v, w, x, y, z}    (Universal Set)

A = {q, s, u, w, y}

B = {q, s, y, z}

C = {v, w, x, y, z}

Consider Set A = {q, s, u, w, y}

A' = U - A = {q, r, s, t, u, v, w, x, y, z} - {q, s, u, w, y} = { r, t, v, x, z }

and Set B = {q, s, y, z}

Now -

A' ∪ B = { r, t, v, x, z }  ∪  {q, s, y, z} = { r, t, v, x, z, q, s, y, z }

Hence, the Set A’∪ B =  { r, t, v, x, z, q, s, y, z }

To solve more questions on Set theory, visit the link below -

brainly.com/question/13042571

#SPJ1

6 0
2 years ago
You live near a bridge that goes over a river. The underneath side of the bridge is an arch that can be modeled with the functio
Alex17521 [72]

Answer:

i believe your answer is B hope this helps

Step-by-step explanation:

:)

8 0
3 years ago
25x^-4-99x^-2-4=0 <br> How do I solve for this?
OlgaM077 [116]

Given

25x^{-4} - 99x^{-2} - 4 = 0

consider substituting y=x^{-2} to get a proper quadratic equation,

25y^2 - 99y - 4 = 0

Solve for y ; we can factorize to get

(25y + 1) (y - 4) = 0

25y+1 = 0 \text{ or } y - 4 = 0

y = -\dfrac1{25} \text{ or }y = 4

Solve for x :

x^{-2} = -\dfrac1{25} \text{ or }x^{-2} = 4

The first equation has no real solution, since x^{-2} = \frac1{x^2} > 0 for all non-zero x. Proceeding with the second equation, we get

x^{-2} = 4 \implies x^2 = \dfrac14 \implies x = \pm\sqrt{\dfrac14} = \boxed{\pm \dfrac12}

If we want to find all complex solutions, we take i=\sqrt{-1} so that the first equation above would have led us to

x^{-2} = -\dfrac1{25} \implies x^2 = -25 \implies x = \pm\sqrt{-25} = \pm5i

8 0
2 years ago
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