Answer:
See Explanation;
Step-by-step explanation:
The given vectors are;
and 
a) To add or subtract two vectors, we add or subtract their corresponding components









b) See attachment for graphs(1,6
Since one bus holds 36 students and 4 adults, 40 people are in one bus so...
40 (6)
=240
Total 240 people are going on the field trip.
Hope this helped you.
Have a great day!
We know that 5x-3x =2x
So x(5x-3x)=x×2x
=(2x)^2
=4x^2
Which is given as 18.
X^2=18÷4
=4.5
So x=root over 4.5
Which is approximately 2.25
Answer:

Time for bacteria count reaching 8019: t = 2.543 hours
Step-by-step explanation:
To find the composite function N(T(t)), we just need to use the value of T(t) for each T in the function N(T). So we have that:




Now, to find the time when the bacteria count reaches 8019, we just need to use N(T(t)) = 8019 and then find the value of t:


Solving this quadratic equation, we have that t = 2.543 hours, so that is the time needed to the bacteria count reaching 8019.