Given J(1, 1), K(3, 1), L(3, -4), and M(1, -4) and that J'(-1, 5), K'(1, 5), L'(1, 0), and M'(-1, 0). What is the rule that tran
anastassius [24]
(x; y) -> (x - 2; y + 4)
J(1; 1) ⇒ J'(1 - 2; 1 + 4) = (-1; 5)
K(3; 1) ⇒ K'(3 - 2; 1 + 4) = (1; 5)
L(3;-4) ⇒ L'(3 - 2; -4 + 4) = (1; 0)
M(1;-4) ⇒ M'(1 - 2;-4 + 4) = (-1; 0)
Hello! In slope-intercept form, y=mx+b. M is the slope and b is the y-intercept. The rate of change and slope are interchangeable, therefore, they both create a line through the slope-intercept form.
Feel free to rate my answer Brainliest if I helped you!
Answer: 15
Step-by-step explanation: Take 12 and change the -3 to a regular 3.
(12 + 3 = 15.)
Whichever number in the question that’s bigger determines what integer it will have.
Answer:
- 75 - 32y
Step-by-step explanation:
2y-3[3-4(y-5)+2(1-3y)]
= 2y - 3(3 - 4y + 20 + 2 - 6y)
= 2y - 3(25 - 10y)
= 2y - 75 - 30y
= - 75 - 32y
Brainliest???
