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Ahat [919]
3 years ago
6

Y-5=6(x-2) Solve for y using inverse operations

Mathematics
1 answer:
pogonyaev3 years ago
3 0
0,-2 . Ejdhemaokebejjsjebfhw
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Natasha can type 30 words a minute. <br> How many words can be typed in 7.5 minutes?
julia-pushkina [17]
225. I think. However its not clear if total words typed are asked for Natasha or in General.
3 0
3 years ago
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plz help. The amount of pages in a 3rd graders book can be modeled by f(x) = x^2 + 6x where x represents the number of chapters.
posledela

Answer:

we can just plug values in and get x = 9

hope this helps and brainliest please

6 0
3 years ago
Which values of k would cause this system of equations to have no solution? Check all that apply.
xeze [42]

Answer:

x= -2y/3

-4y+4y=14

0y= 14

This has no solution.

Step-by-step explanation:

Answer In cases of two equations having two unknown variables the simultaneous method of solving the equations is adopted.

Supposing “0” as the value of “k” we will have the equation as 3x+2y=0

Then separating variable x will give, x= -2y/3

Substituting the value of x into the first equation that is: 6x + 4y = 14

6(-2y/3)+4y=14

Expanding this we get: 6(-2y/3)+4y=14

-4y+4y=14

0y= 14

Thus, no solution.

5 0
3 years ago
Read 2 more answers
The height of a stuntperson jumping off a building that is 20 m high is modeled by the equation h = 20 -57, where t is the time
cupoosta [38]

A stuntman jumping off a 20-m-high building is modeled by the equation h = 20 – 5t2, where t is the time in seconds. A high-speed camera is ready to film him between 15 m and 10 m above the ground. For which interval of time should the camera film him?

Answer:

1\leq t\geq \sqrt{2}

Step-by-step explanation:

Given:

A stuntman jumping off a 20-m-high building is modeled by the equation

h =20-5t^{2}-----------(1)

A high-speed camera is ready to making film between 15 m and 10 m above the ground

when the stuntman is 15m above the ground.

height h = 15m  

Put height value in equation 1

15 =20-5t^{2}

5t^{2} =20-15

5t^{2} =5

t^{2} =1

t =\pm1

We know that the time is always positive, therefore t=1

when the stuntman is 10m above the ground.

height h = 10m  

Put height value in equation 1

10 =20-5t^{2}

5t^{2} =20-10

5t^{2} =10

t^{2} =\frac{10}{5}

t^{2} =2

t=\pm\sqrt{2}

t=\sqrt{2}

Therefore ,time interval of camera film him is 1\leq t\geq \sqrt{2}

7 0
3 years ago
-5=5(d+4)<br> Please give step by step
bekas [8.4K]

Answer:

  1. first distribute the 5 to the d and 4
  2. 5(d+4) then becomes 5d+20
  3. then subtract 20 from both sides of the equation
  4. -5=5d+20 is now -25=5d
  5. lastly divide 5 from both sides
  6. -25=5d is now -5=d
  7. hope this helps!
6 0
3 years ago
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