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NemiM [27]
3 years ago
11

When called upon to give an impromptu speech, it is a good idea to do all of the following, except:

Computers and Technology
2 answers:
schepotkina [342]3 years ago
5 0
C. Taking a long time to decide your message

Since it's impromptu I would think you'd want to think about what you'd say quickly. (I'm pretty sure)
RideAnS [48]3 years ago
5 0

Answer:

c.  take a long time deciding what your message will be

Explanation:

When called upon to give an impromptu speech, it is not a good idea to take a long time deciding what your message will be because impromptu means that you were called in the spur of the moment, so you can't take a lot of time as you will need to speak inmediately.

Also, start off strong and with confidence, decide on your transitions from one point to the other and maintain eye contact with the audience are things that you should do and that will help you to deliver the message appropiately to the audience.

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Answer:

You can.

Explanation:

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What is a way to minimize techniacl problems with your computer.
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two Smallest (10 points). Write a program TwoSmallest.java that takes a set of double command-line arguments and prints the smal
Umnica [9.8K]

Answer:

Below is the program TwoSmallest.java with each step explanation in form of comments.

public class TwoSmallest {                     // class definition

//main class having string args as a parameter

   public static void main(String[] args)

{ if (args.length < 2)

{         //string length must not be less than 2 for proceeding

           System.out.println("Please provide double values as command line arguments");

  }

else {  

// first two entries of string are checked for min1 and min2 and stored in variables with data type double

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//when min1 will be greater than min2 it will be stored temporary in variable temp having data type double

           if (min1 > min2) {

               double temp = min1;

               min1 = min2;

               min2 = temp;  //value of temp will be stored in min2

           }

//loop will check for each entry remaining until the last character of string

           for (int i = 2; i < args.length; i++) {

               num = Double.parseDouble(args[i]);

               if (num < min1) {

                   min2 = min1;

                   min1 = num;

               } else if (num < min2) {

                   min2 = num;

               }

           }

//min1 will give the 1st minimum number and min2 will give 2nd minimum.

           System.out.println(min1);

           System.out.println(min2);  

//both characters will be printed in sequence

       }

   }

}

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Answer:

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Explanation:

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Natasha2012 [34]

Answer:

Explanation:

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