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viva [34]
3 years ago
10

Why is the international bureau of weight and measure established​

Physics
2 answers:
Reptile [31]3 years ago
6 0

Answer:

Explanation:

International Bureau of Weights and Measures (BIPM), French Bureau International des Poids et Mesures, international organization founded to bring about the unification of measurement systems, to establish and preserve fundamental international standards and prototypes, to verify national standards, and to determine standard units.

Cloud [144]3 years ago
4 0

Explanation:

International Bureau of Weights and Measures (BIPM), French Bureau International des Poids et Mesures, international organization founded to bring about the unification of measurement systems, to establish and preserve fundamental international standards and prototypes, to verify national standards

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If a 15 N box is lifted a distance of 3 m, how much work is done?
Naily [24]

Answer:

W=45J

Explanation:

W=Fd

W=15(3)=45

W=45J

7 0
3 years ago
Read 2 more answers
Make the following conversion. 425 g = _____kg 0.425 0.0425 4,250 425,000
blsea [12.9K]
0.425
BECAUSE 1000g makes 1Kg
so 425g will make 0.425 option a
6 0
4 years ago
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The gravity on mars is 3.8 m/s2 and you weigh 200 N. your mass will be??
lisabon 2012 [21]

Answer:

Mass = 52.63 kilograms

Explanation:

Given the following data;

Acceleration due to gravity = 3.8 m/s²

Weight = 200 N

To find mass;

Mathematically, the weight of a physical object is given by the formula;

Weight = mass * acceleration due to gravity

Substituting into the formula, we have;

200 = mass * 3.8

Mass = 200/3.8

Mass = 52.63 kg

3 0
3 years ago
Problem 12.78 Determine the mass of the earth knowing that the mean radius of the moon’s orbit about the earth is 238,910 mi and
Gennadij [26K]

Answer:

M_e = 6.04 * 10^24 kg

Explanation:

Given:

- The time period of moon orbit T = 27.32 days

- Distance from center of earth to moon r = 238,910 miles

- The gravitational constant G = 6.67408 * 10^-11

Find:

- Determine the mass of the earth

Solution:

- The mass of earth as a function of time period T and radius of orbit r is related by an expression as follows:

                   M_e = (2*pi / T)^2 * (r^3 / G)

                   M_e = (2*pi / 27.32*24*60*60)^2 * (238910*1609 / 6.67408 *10^-11)

                  M_e = 6.04 * 10^24 kg

8 0
4 years ago
In about 5 billion years, at the end of its lifetime, our sun will end up as a white dwarf, having about the same mass as it doe
vitfil [10]
It is fine to use the equation given by Plitter, since we are told that the mass is about the same as it is now, and I seriously doubt the original question wants the student to go into relativistic effects, electron degeneracy pressure and magnetic effects that govern a real white dwarf star.
There is no need to make it unnecessarily complicated, when the question is set at high school level.  The question asks, given a particular radius, and a given mass, what will the density be (which in this case will be the average density).   To answer the question, one needs to know the mass of the sun (which is about 2×1030 Kg.  One needs to convert the diameter to a radius, and then calculate the spherical volume of the white dwarf.  Then one can use the formula given above, namely density=mass/volume
8 0
3 years ago
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