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2 years ago

If a 15 N box is lifted a distance of 3 m, how much work is done?

Physics

2 answers:

Naily [24]2 years ago

7 0

Answer:

W=45J

Explanation:

W=Fd

W=15(3)=45

W=45J

Oxana [17]2 years ago

5 0

Answer:

work done = 45 j

Explanation:

work done ( W.D ) = force × displacement

=》W.D = 15 N × 3 m = 45 joule

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If vx=9.80 units and vy=-6.40 units, determine the magnitude and direction of v

dexar [7]

The resultant vector can be determined by the component vectors. The component vectors are vector lying along the x and y-axes. The equation for the resultant vector, v is:

v = √(vx² + vy²)
v = √[(9.80)² + (-6.40)²]
v = √137 or 11.7 units

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3 years ago

Why are such scientific advances still valuable?

Sergeu [11.5K]

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3 years ago

What do conduction, radiation, and convection work together to do?

Semmy [17]

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6 0

3 years ago

Enzyme reaction and deactivation Lipase is being investigated as an additive to laundry detergent for removal of stains from fab

natita [175]

Answer:

t= 27.38 mins [this the time taken by the enzyme to hydrolyse 80% of the fat present]

Explanation:given values

Half life of lipase t_1/2 = 8 min x 60s/min = 480 s

Rate constant for first order reaction

k_d = 0.6932/480 = 1.44 x 10^-3 s-1

Initial fat concentration S_0 = 45 mol/m3 = 45 mmol/L

rate of hydrolysis Vm0 = 0.07 mmol/L/s

Conversion X = 0.80

Final concentration S = S_0(1-X) = 45 (1-0.80) = 9 mol/m3

K_m = 5mmol/L

time take is given by

$t= -\frac{1}{K_d}ln[1-\frac{K_d}{V_m_0}(k_mln\frac{s_0}{s}+(s_0-s))]$

all values are given and putting these value we get

t=1642.83 secs

which is equal to

t= 27.38 mins [this the time taken by the enzyme to hydrolyse 80% of the fat present]

5 0

3 years ago

You are pushing a wooden crate across the floor at constant speed. You decide to turn the crate on end, reducing by half the sur

borishaifa [10]

Answer:

D. Half as great

Explanation:

Since we know that the friction force between the surface of crate and ground is given as

$F_f = \mu F_n$

so here we know that

$\mu$ = friction coefficient between two surfaces which depends on the effective contact area between two surfaces

$F_n$ = normal force due to the object

So when we turn the object on another side such that the surface area is half then the friction coefficient will become also half

So here the friction force will also reduce to half

so correct answer will be

D. Half as great

3 0

3 years ago