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3 years ago

The reason an electric current can create a magnetic field is due to the phenomenon of

Physics

1 answer:

Alex Ar [27]3 years ago

8 0

Electromagnetic induction

Explanation:

Electromagnetic induction is defined as the production of voltage using the magnetic created by the electric current.
The magnetic field is one of the components of electric lines. The other component is the electric field
When the electricity is passed through a metallic conductor is acts as a temporary magnets
Electromagnetic induction happens when the flux lines around a magnetic field are cut by the coils.
The field lines in the permanent or temporary magnets are always from the North pole to south pole.

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3 years ago

A water rocket uses an amount of water and pressurized air to send a plastic rocket several feet into the air. As the water and

Ilya [14]

Answer:

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Explanation:

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3 years ago

The age of a piece of wood from an archeological site is to be determined using the Carbon-14 method. The activity of the sample

Bezzdna [24]

Answer:

4589.05 year

Explanation:

The relation of activity is given by $A=A_0e^{\lambda t}$ we have given $\frac{A}{A_0}=0.574$

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We know that half life $T=\frac{0.693}{\lambda }$

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So $0.574=e^{-1.2094\times 10^{-4}t}$

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3 years ago

An electric field of 8.20 ✕ 105 V/m is desired between two parallel plates, each of area 25.0 cm2 and separated by 2.45 mm. Ther

astraxan [27]

Answer:

q = 1.815 \times 10^{-8} C

Charge on one plate is positive in nature and on the other plate it is negative in nature.

Explanation:

E = 8.20 x 10^5 V/m, A = 25 cm^2, d = 22.45 mm

According to the Gauss's theorem in electrostatics

The electric field between the two plates

$E = \frac{\sigma }{\varepsilon _{0}}$

${\sigma }= E \times {\varepsilon _{0}}$

${\sigma }= 8.20 \times 10^{5} \times {8.854 \times 10^{-12}$

${\sigma }= 7.26 \times 10^{-6} C/m^{2}$

Charge, q = surface charge density x area

$q = 7.26 \times 10^{-6} \times 25 \times 10^{-4}$

q = 1.815 \times 10^{-8} C

5 0

3 years ago

Charge q is 1 unit of distance away from the source charge S. Charge p is two times further away. The force exerted between S an

insens350 [35]

Answer : The correct option is, (d) 4 times

Solution :

According to the Coulomb's law, the electrostatic force of attraction or repulsion between two charges is directly proportional to the product of the charges and is inversely proportional to the square of the distance between the the charges.

Formula used :

$F=k_e\frac{q_1q_2}{r^2}$

where,

F = electrostatic force of attraction or repulsion

$k_e$ = Coulomb's constant

$q_1$ and $q_2$ are the charges

r = distance between two charges

First we have to calculate the force exerted between S and q when the distance between the charge is 1 unit and let us assumed that the charge be 'q'

$F_{sq}=k_e\frac{qq}{1^2}=k_e\times q^2$ ..........(1)

Now we have to calculate the force exerted between S and p when the distance between the charge is 2 unit at the same charge.

$F_{sp}=k_e\frac{qq}{2^2}=k_e\frac{q^2}{4}$ ...........(2)

Equation equation 1 and 2, we get

$\frac{F_{sq}}{F_{sp}}=\frac{1}{4}$

$F_{sq}=4\times F_{sp}$

Therefore, the force exerted between S and q is 4 times the force exerted between S and p.

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3 years ago

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