Question

Suppose a second player standing at (90,40) misses the ball, turns around and runs on a path parallel to the baseballs path. What is an equation of the line representing this players path?

Answer 1

Answer:

y = (1/3)x + 10.

Step-by-step explanation:

The path of the baseball is shown in the image below. We can see that the baseball passes through the point (0, 0) and (60, 20). The equation of the baseball path is gotten using the formula:

$y-y_1=\frac{y_2-y_1}{x_2-x_1} (x-x_1)\\\\y-0=\frac{20-0}{60-0} (x-0)\\\\y=\frac{1}{3}x$

The equation of a straight line is given as y = mx + b, where m is the slope, b is the y intercept

The slope of the baseball path is 1/3

The second player is at (90, 40) and runs parallel to the baseball path.

If two lines are parallel then they have the same slope.

Since the player moves parallel to the baseball path, the slope would also be 1/3. The equation of the players path is gotten using:

$y-y_1=m(x-x_1)\\\\y-40=\frac{1}{3}(x-90)\\\\y= \frac{1}{3}x - 30+40\\\\y=\frac{1}{3}x+10$