Use differentiation to show that the given function is a solution of the equation for all values of the constants. (Enter your a
1 answer:
Answer with Step-by-step explanation:
We are given that
DE
Function:
We have to show that given function is a solution of the equation for all values of the constants.
If given function is solution of DE then it satisfied the given DE.
Differentiate function w.r.t.t
Again differentiate w.r.t. t
Substitute the values in the given DE
LHS=RHS
Given function satisfied the given DE.Therefore, it is solution of given DE for all values of the constants.
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Answer:
Unfortunately, your answer is not right.
Step-by-step explanation:
The functions whose graphs do not have asymptotes are the power and the root.
The power function has no asymptote, its domain and rank are all the real.
To verify that the power function does not have an asymptote, let us make the following analysis:
The function , when x approaches infinity, where does y tend? Of course it tends to infinity as well, therefore it has no horizontal asymptotes (and neither vertical nor oblique)
With respect to the function we can verify that if it has asymptote horizontal in y = 0. Since when x approaches infinity the function is closer to the value 0.
For example: 1/2 = 0.5; 1/1000 = 0.001; 1/100000 = 0.00001 and so on. As "x" grows "y" approaches zero
Also, when x approaches 0, the function approaches infinity, in other words, when x tends to 0 y tends to infinity. For example: 1 / 0.5 = 2; 1 / 0.1 = 10; 1 / 0.01 = 100 and so on. This means that the function also has an asymptote at x = 0