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3 years ago

8

Can you solve this? It's listed below lol need more characters hurry please

2 answers:

Natalija [7]3 years ago

6 0

Step-by-step explanation:

sorry I need these points

dalvyx [7]3 years ago

5 0

Answer:

k

Step-by-step explanation:

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What is the exact value of sin 48 degrees?

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Three interior angles of a polygon are,100degrees,120degrees,and 108degrees.Find the remaining two sides,if one of them is three

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2 years ago

Which of the points listed below is not on the line with equation 7y+2=3x-5

kicyunya [14]

Answer: Second option.

Step-by-step explanation:

Given the folllowing Linear Equation:

$7y+2=3x-5$

You need to substitute the coordinates of each point given in the options into the equation and then evaluate.

1) Substituting $(2, -\frac{1}{7})$ into the equation, you get:

$7(-\frac{1}{7})+2=3(2)-5\\\\-1+2=6-5\\\\1=1\ (TRUE)$

2) Substituting the point $(3, -\frac{3}{7})$ . you get:

$7(-\frac{3}{7})+2=3(3)-5\\\\-3+2=9-5\\\\-1=4\ (FALSE)$

3) Apply the same procedure using the point $(1, -\frac{4}{7})$ :

$7(-\frac{4}{7})+2=3(1)-5\\\\-4+2=3-5\\\\-2=-2\ (TRUE)$

4) Apply the same procedure using the point $(-1, -\frac{10}{7})$

$7(-\frac{10}{7})+2=3(-1)-5\\\\-10+2=-3-5\\\\-8=-8\ (TRUE)$

5) Substituting $(0,-1)$ into the equation:

$7(-1)+2=3(0)-5\\\\-7+2=-0-5\\\\-5=-5\ (TRUE)$

Therefore, the point $(3, -\frac{3}{7})$ is not on the given line.

8 0

3 years ago

The partial fraction decomposition of 9 x 11 6 x 2 23 x 21 can be written in the form of f ( x ) 2 x 3 g ( x ) 3 x 7 , where

svlad2 [7]

Answer:

$f(x) = -1$

$g(x) =6$

$\frac{-1}{2x + 3} + \frac{6}{3x + 7}$

Step-by-step explanation:

The question is unreadable, however the real polynomial is:

The polynomial fraction is:

$P = \frac{9x + 11}{6x^2 + 23x + 21}$

And the decomposition is:

$\frac{f(x)}{2x + 3} + \frac{g(x)}{3x + 7}$

The solution is as follows:

$P = \frac{f(x)}{2x + 3} + \frac{g(x)}{3x + 7}$

Substitute the expression for P

$\frac{9x + 11}{6x^2 + 23x + 21} = \frac{f(x)}{2x + 3} + \frac{g(x)}{3x + 7}$

Expand the numerator of the polynomial

$\frac{9x + 11}{(2x + 3)(3x + 7)} = \frac{f(x)}{2x + 3} + \frac{g(x)}{3x + 7}$

Take LCM

$\frac{9x + 11}{(2x + 3)(3x + 7)} = \frac{f(x)*(3x + 7) + g(x)*(2x + 3)}{(2x + 3)(x + 7)}$

Cancel out both denominators

$9x + 11} = f(x)*(3x + 7) + g(x)*(2x + 3)$

Represent f(x) as A and g(x) as B

$9x + 11} = A*(3x + 7) + B*(2x + 3)$

Open bracket

$9x + 11} = 3Ax + 7A + 2Bx + 3B$

$9x + 11} = 3Ax + 2Bx+ 7A + 3B$

$9x + 11} = (3A + 2B)x+ 7A + 3B$

By comparison:

$3A + 2B = 9$ ---- (1)

$7A + 3B =11$ ---- (2)

Make B the subject in (1)

$B = \frac{9 - 3A}{2}$

Substitute $B = \frac{9 - 3A}{2}$ in (2)

$7A + 3(\frac{9 - 3A}{2}) = 11$

Multiply through by 2

$2*7A +2* 3(\frac{9 - 3A}{2}) = 11*2$

$14A + 3(9 - 3A) = 22$

$14A + 27 - 9A = 22$

Collect Like Terms

$14A - 9A = 22-27$

$5A = -5$

$A = \frac{-5}{5}$

$A = -1$

Recall that:

$B = \frac{9 - 3A}{2}$

$B = \frac{9 - 3 * -1}{2}$

$B = \frac{9 + 3}{2}$

$B = \frac{12}{2}$

$B = 6$

A = -1 and B = 6

$3A + 2B = 9$ ---- (1)

$7A + 3B =11$ ---- (2)

So:

$f(x) = A$

$f(x) = -1$

$g(x) =B$

$g(x) =6$

And the decomposition is:

$\frac{-1}{2x + 3} + \frac{6}{3x + 7}$

6 0

2 years ago