Answer:
the funtion does not satisfies the hypothese f(a)=f(b), just because when evaluate f(0) = 1 and when evaluate f(2) = 11,
<h3>
Answer: sin(2x)</h3>
In other words, you'll type "sin" without quotes in the green box.
Also, you'll type "2" in the gray box, which also won't have quotes.
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Explanation:
We'll use the first hint. Note the pattern of sin cos +- cos sin which matches (somewhat) with the original expression.
Specifically, we'll use this identity
sin(A - B) = sin(A)cos(B) - cos(A)sin(B)
In this case, A = 3x and B = x
So,
sin(A - B) = sin(A)cos(B) - cos(A)sin(B)
sin(A)cos(B) - cos(A)sin(B) = sin(A - B)
sin(3x)cos(x) - cos(3x)sin(x) = sin(3x - x)
sin(3x)cos(x) - cos(3x)sin(x) = sin(2x)
Answer:
-3 , 6
Step-by-step explanation:
- <em><u>(</u></em><em><u>4</u></em><em><u>)</u></em><em><u> </u></em><em><u>×</u></em><em><u> </u></em><em><u>(</u></em><em><u>-</u></em><em><u>3</u></em><em><u>)</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>-12</u></em>
- <em><u>(</u></em><em><u>-</u></em><em><u>2</u></em><em><u>)</u></em><em><u> </u></em><em><u>×</u></em><em><u> </u></em><em><u>(</u></em><em><u>6</u></em><em><u>)</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>-12</u></em>
<em><u>HOPE</u></em><em><u> </u></em><em><u>IT</u></em><em><u> </u></em><em><u>MAY</u></em><em><u> </u></em><em><u>HELP</u></em><em><u> </u></em><em><u>YOU</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>
Y2-y1/x2-x1 = m
10-12/4-1 = m
-2/3 = m
Slope is -2/3
The answer is x=4 or x= -5/2 or x =0