Solve your system of equations step by step.
x−2y=14;x+3y=9
Solve x−2y=14 for x:
x−2y+2y=14+2y (Add 2y to both sides)
x=2y+14
Substitute (2y+14) for x in x+3y=9:
x+3y=9
2y+14+3y=9
5y+14=9(Simplify both sides of the equation)
5y+14+−14=9+−14 (Add -14 to both sides)
5y=−5
5y5=−55 (Divide both sides by 5)
y=−1
Substitute (−1) for y in x=2y+14:
x=2y+14
x=(2)(−1)+14
x=12(Simplify both sides of the equation)
So,
y=-1
x=12
Answer is C)
6.50x + 5.25y + 15.25 <<span> 45
6.50(2)+5.25(3)+15.25<45
44<45
</span>
No because the total will be $44.
SOLUTION
Since the can is a cylinder, we will use the formula for volume of a cylinder to solve the problem.
Volume of a cylinder is given as

Applying we have

Hence the answer is 3.8, the second option is the answer
Answer:
<h2>See the explanation and the image.</h2>
Step-by-step explanation:
The inequality
means
.
y = 0, satisfies the above inequality, so the arrows will be towards the x axis.
Now, we need to draw 5x < 8 + 4y.
First, lets draw the equation of 5x = 8 + 4y.
y = 1 gives x = 2.4 & y = 0 gives x = 1.6.
Hence, the above equation passes through (2.4, 1) and (1.6, 0).
The point (0, 0) satisfies the inequality 5x < 8 + 4y. Hence, the arrows will be towards the origin.
The solution will be the area of APQ except any point on PQ, as PQ is nothing but the line 5x = 8 + 4y.
The perimeter of ADC is 9.5 cm.