Answer:
Zero (0)
Explanation:
According to the given information the genotype of the woman with blood type "AB" would by I^AI^B. The genotype of the man with blood type O would be "ii". Here, the alleles I^A and I^B are dominant over the allele "i".
A cross between parents with genotype I^AI^B and ii would give 50% of children with I^Ai genotype and 50% of children with I^Bi genotype. The children with "I^Ai genotype" would have blood type "A" and the children with I^Bi genotype would have blood type "B". This couple is never likely to have any child with blood type "O" since the mother does not carry allele "i".
Cross: I^AI^B x ii = 1/2 I^Ai : 1/2 I^Bi
Livestock candidates should be chosen based on the patient's preference as there could be organ rejection is an unbiased argument.
<h3>What is an Unbiased argument?</h3>
This type of argument shows the reader both sides and bids the reader decide.
The other options tends to support an animal which makes them biased but option D doesn't and has a credible reason which is why it's the most appropriate choice.
Read more about Unbiased argument here brainly.com/question/2399804