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IRISSAK [1]
3 years ago
5

HELPPP!!! What would the mass of an artificial cell containing 20mL of a 25% sugar solution be after it was placed in a beaker c

ontaining a 30% sugar solution for 30 minutes? Remember to include units in your answer.
Biology
1 answer:
zaharov [31]3 years ago
5 0

Answer: The sugar will move from the 50 % concentration to the 0 % concentration.

Explanation:

Dialysis is an analytical technique which uses a semipermeable membrane in order to remove the impurities from the body.

This technique is used when the kidney failure inside the body takes place. The kidney inside the body perform function of filtration, when kidney failure takes place then the dialysis is used.

In this case the tubing bag containing 0% sugar is put into a sugar solution having 50% solution.

After sometime the sugar will move from 50 % to 0% bag because of the phenomenon known as osmosis.

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3 years ago
Use the key to identify each species. Write the letter of each species (A to G) in the correct
sveticcg [70]

Dichotomous keys are useful to identify organisms according to their morphological traits. The given key provides enough macroscopic morphological traits to identify these Arachnida species.

-----------------------------------------------

A dichotomous key is a significantly useful tool to classify organisms. The key provides an easy and fast way for identification by describing different morphological traits, leading you to the correct taxonomic classification.

The key provides morphological descriptions about different taxonomic groups in an easy way to identify these traits in your individual.

The term <em>dichotomous</em> refers to how information is provided. You will always have two options (a and b, or 1 and 2), and you will have to choose one of them according to the characteristics of your organism.  

In the exposed example, as the key provides morphological traits, we will separate the organisms<u><em> into two groups</em></u>:

  • the group that has the trait
  • the group that does not have it.

By recognizing each trait in each of the individuals, we will get to identify the species.

1

(a)  Abdomen <u>with a </u><u>tail</u> --------------------------- The only option is E

(b)  Abdomen <u>without a </u><u>tail</u><u> </u>----------------------  All the others A, B, C, D, F, G

2  ---<em>Only for  group A, B, C, D, F, G---</em>

(a) <u>Legs</u><u> much longer </u>than abdomen and  cephalothorax ----------A and G

(b)<u> </u><u>Legs</u><u> not much longer</u> than abdomen and  cephalothorax----- B, C, D, F

3  ---<em>Only for  group A, G---</em>

(a) <u>Hairs</u> on the legs -----------------------------------The only option is A

(b) <u>No hairs</u> on the legs ------------------------------ G

4  ---<em>Only for  group B, C, D, F---</em>

(a) Cephalothorax or <u>abdomen</u><u> segmented</u> ----------------The only option is D

(b) Cephalothorax or a<u>bdomen not segmented</u> ----------- B, C, F

5  ---<em>Only for  group  B, C, F---</em>

(a) Abdomen and cephalothorax <u>of the same size</u> --------The only option is F

(b) Abdomen and cephalothorax <u>of different size</u> -------B, C

6  ---<em>Only for  group B, C---</em>

(a) Body <u>covered with long</u><u> hair</u><u> </u>----------------------------------The only option is C

(b) Body<u> </u><u>not covered with</u><u> hair</u> ------------------------------------B

A  →  <em>Tegenaria domestica</em>

B  →  <em>Ixodes hexagonus</em>

C  →  <em>Tyroglyphus longior</em>

D  →  <em>Chelifer tuberculatus</em>

E  →  <em>Abaliella dicranotarsalis</em>

F  →   <em>Poecilotheria regalis</em>

G  →  <em>Odielus spinosus</em>

---------------------------------------------------

Related link: brainly.com/question/2235448?referrer=searchResults  

                    brainly.com/question/17365165?referrer=searchResults  

4 0
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