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3 years ago

I need help with this ASAP

Mathematics

2 answers:

8_murik_8 [283]3 years ago

6 0

Answer:

Step-by-step explanation

I think its D

lidiya [134]3 years ago

3 0

B - Colored in, arrow to the left

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Find the value of csc theta, if cos =-3/5; 90 degrees < theta < 180 degrees

Sloan [31]

Answer: $\frac{5}{4}$

Step-by-step explanation:

Given

$\cos \theta =\frac{-3}{5}$

and $\theta$ lies between

$90^{\circ}$

and for this $\theta$ , $\sin$ and $\text{cosec}$ is Positive as they lie in 2 nd Quadrant

$\sin ^2\theta +\cos ^2\theta =1$

$\sin ^2\theta =1-(\frac{-3}{5})^2$

$\sin ^2\theta =1-\frac{9}{25}$

$\sin ^2\theta =\frac{16}{25}$

$\sin \theta =\frac{4}{5}$

$\therefore \text{cosec}\ \theta =\frac{5}{4}$

6 0

3 years ago

In Triangle XYZ, measure of angle X = 49° , XY = 18°, and

marissa [1.9K]

Answer:

There are two choices for angle Y: $Y \approx 54.987^{\circ}$ for $XZ \approx 15.193$ , $Y \approx 27.008^{\circ}$ for $XZ \approx 8.424$ .

Step-by-step explanation:

There are mistakes in the statement, correct form is now described:

<em>In triangle XYZ, measure of angle X = 49°, XY = 18 and YZ = 14. Find the measure of angle Y:</em>

The line segment XY is opposite to angle Z and the line segment YZ is opposite to angle X. We can determine the length of the line segment XZ by the Law of Cosine:

$YZ^{2} = XZ^{2} + XY^{2} -2\cdot XY\cdot XZ \cdot \cos X$ (1)

If we know that $X = 49^{\circ}$ , $XY = 18$ and $YZ = 14$ , then we have the following second order polynomial:

$14^{2} = XZ^{2} + 18^{2} - 2\cdot (18)\cdot XZ\cdot \cos 49^{\circ}$

$XZ^{2}-23.618\cdot XZ +128 = 0$ (2)

By the Quadratic Formula we have the following result:

$XZ \approx 15.193\,\lor\,XZ \approx 8.424$

There are two possible triangles, we can determine the value of angle Y for each by the Law of Cosine again:

$XZ^{2} = XY^{2} + YZ^{2} - 2\cdot XY \cdot YZ \cdot \cos Y$

$\cos Y = \frac{XY^{2}+YZ^{2}-XZ^{2}}{2\cdot XY\cdot YZ}$

$Y = \cos ^{-1}\left(\frac{XY^{2}+YZ^{2}-XZ^{2}}{2\cdot XY\cdot YZ} \right)$

1) $XZ \approx 15.193$

$Y = \cos^{-1}\left[\frac{18^{2}+14^{2}-15.193^{2}}{2\cdot (18)\cdot (14)} \right]$

$Y \approx 54.987^{\circ}$

2) $XZ \approx 8.424$

$Y = \cos^{-1}\left[\frac{18^{2}+14^{2}-8.424^{2}}{2\cdot (18)\cdot (14)} \right]$

$Y \approx 27.008^{\circ}$

There are two choices for angle Y: $Y \approx 54.987^{\circ}$ for $XZ \approx 15.193$ , $Y \approx 27.008^{\circ}$ for $XZ \approx 8.424$ .

6 0

3 years ago

If the area of the square is A(s) = s², find the formula for the area as a function of time, and then determine A(s(3)).

Oxana [17]

A(t) = 100t^2 + 500t + 625

3,025 square pixels

5 0

3 years ago

Read 2 more answers

According to the Ruler Postulate, what does the set of points on any line correspond to?

sdas [7]

They correspond to any real number.

5 0

4 years ago

Read 2 more answers

grandymaker [24]

Answer:

2 seconds
72 feet

Step-by-step explanation:

The usual equation used for the vertical component of ballistic motion is ...

h(t) = -16t² +v₀t +h₀

where v₀ is the initial upward velocity, and h₀ is the initial height. Units of distance are feet, and units of time are seconds.

Your problem statement gives ...

v₀ = 64 ft/s

h₀ = 8 ft

so the equation of height is ...

h(t) = -16t² +64t +8

For quadratic ax² +bx +c, the axis of symmetry is x=-b/(2a). Then the axis of symmetry of the height equation is ...

t = -64/(2(-16)) = 2

The object will reach its maximum height after 2 seconds.

The height at that time will be ...

h(2) = -16(2²) +64(2) +8 = 72

The maximum height will be 72 feet.

5 0

3 years ago