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Maurinko [17]
3 years ago
10

Find the value of csc theta, if cos =-3/5; 90 degrees < theta < 180 degrees

Mathematics
1 answer:
Sloan [31]3 years ago
6 0

Answer:\frac{5}{4}

Step-by-step explanation:

Given

\cos \theta =\frac{-3}{5}

and \theta  lies between

90^{\circ}

and for this \theta,\sin and \text{cosec} is Positive as they lie in 2 nd Quadrant

\sin ^2\theta +\cos ^2\theta =1

\sin ^2\theta =1-(\frac{-3}{5})^2

\sin ^2\theta =1-\frac{9}{25}

\sin ^2\theta =\frac{16}{25}

\sin \theta =\frac{4}{5}

\therefore \text{cosec}\ \theta =\frac{5}{4}

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