Answer:
Step-by-step explanation:
Flip the equation.
−px+6x+8=z
Add -8 to both sides.
−px+6x+8+−8=z+−8
−px+6x=z−8
Factor out variable x.
x(−p+6)=z−8
Divide both sides by -p+6.
hope this helps
Which of the following does not dissolve in water
1 answer:
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Answer:
We Reject H₀ if t calculated > t tabulated
But in this case,
0.83 is not greater than 2.056
Therefore, we failed to reject H₀
There is no difference between the mean pulse rate of people who do not exercise and the mean pulse rate of people who do exercise.
Step-by-step explanation:
Refer to the attached data.
The Null and Alternate hypothesis is given by
Null hypotheses = H₀: μ₁ = μ₂
Alternate hypotheses = H₁: μ₁ ≠ μ₂
The test statistic is given by
Where is the sample mean of people who do not exercise regularly.
Where is the sample mean of people who do exercise regularly.
Where is the sample standard deviation of people who do not exercise regularly.
Where is the sample standard deviation of people who do exercise regularly.
Where is the sample size of people who do not exercise regularly.
Where is the sample size of people who do exercise regularly.
The given level of significance is
1 - 0.95 = 0.05
The degree of freedom is
df = 16 + 12 - 2 = 26
From the t-table, df = 26 and significance level 0.05,
t = 2.056 (two-tailed)
Conclusion:
We Reject H₀ if t calculated > t tabulated
But in this case,
0.83 is not greater than 2.056
Therefore, We failed to reject H₀
There is no difference between the mean pulse rate of people who do not exercise and the mean pulse rate of people who do exercise.
SOLUTION:
Case: Hypothesis testing
Step 1: Null and Alternative hypotheses
Step 2: T-test analysis
Step 3: t-test with the significance level
Step 4: Comparing
So tail to reject the null hypothesis. There is enough evidence at a 0.05 level of significance to claim that the mean spent is greater than P127.50.
Final answer:
Yes, there is evidence sufficient to conclude that the mean amount spent is greater than P127.50 per month at a 0.05 level of significance.
Answer:
The mean number of adults who would have bank savings accounts is 32.
Step-by-step explanation:
For each adult surveyed, there are only two possible outcomes. Either they have bank savings accounts, or they do not. So we use the binomial probability distribution to solve this problem.
Binomial probability distribution
Probability of exactly x sucesses on n repeated trials, with p probability.
The expected value of the binomial distribution is:
In this problem, we have that:
If we were to survey 50 randomly selected adults, find the mean number of adults who would have bank savings accounts.
This is E(X) when .
So
The mean number of adults who would have bank savings accounts is 32.