True. For example, if 2 is a, and b was 0, then ab would automatically be 0. Both a and b can be 0 though, but at least one of them must be zero.
Answer:
Range for third side is
(
5
,
25
) cm.
Step-by-step explanation:
As two sides of triangle are 10 and 15
,
the third side would have to be less than the sum of other two sides i.e. less than 25 cm.
On the other hand if it is smaller one than this side plus side of length 10
should be greater than 15 and therefore
this side is greater than 15
−
10
=
5 cm.
Hence range is
(
5
,
25
)
Hope this answer helps you :)
Have a great day
Mark brainliest
Hey there! :)
Answer:
x = 21 units.
Step-by-step explanation:
Since we know Figure A is just Figure B scaled, we can set up a proportion:

Cross multiply to solve for x:
45 · x = 35 · 27
45x = 945
Divide both sides by 45:
x = 21 units.
Answer:
The probability is 1/2
Step-by-step explanation:
The time a person is given corresponds to a uniform distribution with values between 0 and 100. The mean of this distribution is 0+100/2 = 50 and the variance is (100-0)²/12 = 833.3.
When we take 100 players we are taking 100 independent samples from this same random variable. The mean sample, lets call it X, has equal mean but the variance is equal to the variance divided by the length of the sample, hence it is 833.3/100 = 8.333.
As a consecuence of the Central Limit Theorem, the mean sample (taken from independant identically distributed random variables) has distribution Normal with parameters μ = 50, σ= 8.333. We take the standarization of X, calling it W, whose distribution is Normal Standard, in other words

The values of the cummulative distribution of the Standard Normal distribution, lets denote it
, are tabulated and they can be found in the attached file, We want to know when X is above 50, we can solve that by using the standarization
