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Dahasolnce [82]
3 years ago
13

Abeeta bought 3 3/4 kg apple and 4 1/2 kg guava what is the total weight of fruit purchased by her​

Mathematics
1 answer:
Natali5045456 [20]3 years ago
6 0

Answer:

that might me 8.25 kg bro

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A family of 4 spent $104 for tickets to a concert on Friday and they spent $140 for tickets to a dinner theater on Saturday. All
Julli [10]

Answer:

  • Friday's tickets: $26 each
  • Saturday's tickets: $35 each

Step-by-step explanation:

We presume that 4 tickets were bought each day, so the price of 1 ticket is 1/4 of the total price:

  (1/4)($104) = $26

  (1/4)($140) = $35

The cost of each ticket on Friday was $26; on Saturday, the cost was $35.

5 0
3 years ago
248 students went on a trip to the zoo. All 6 buses were filled and 8 students had to travel in cars. How many students were in
PIT_PIT [208]
40 students on each bus. 248 minus 8 equals 240. 240 divides by 6 equals 40.
5 0
3 years ago
Read 2 more answers
1. Write the form of the partial fraction decomposition of the rational expression. Do not solve for the constants.
german

Answer:

Step-by-step explanation:

1.

To write the form of the partial fraction decomposition of the rational expression:

We have:

\mathbf{\dfrac{8x-4}{x(x^2+1)^2}= \dfrac{A}{x}+\dfrac{Bx+C}{x^2+1}+\dfrac{Dx+E}{(x^2+1)^2}}

2.

Using partial fraction decomposition to find the definite integral of:

\dfrac{2x^3-16x^2-39x+20}{x^2-8x-20}dx

By using the long division method; we have:

x^2-8x-20 | \dfrac{2x}{2x^3-16x^2-39x+20 }

                  - 2x^3 -16x^2-40x

                 <u>                                         </u>

                                            x+ 20

So;

\dfrac{2x^3-16x^2-39x+20}{x^2-8x-20}= 2x+\dfrac{x+20}{x^2-8x-20}

By using partial fraction decomposition:

\dfrac{x+20}{(x-10)(x+2)}= \dfrac{A}{x-10}+\dfrac{B}{x+2}

                         = \dfrac{A(x+2)+B(x-10)}{(x-10)(x+2)}

x + 20 = A(x + 2) + B(x - 10)

x + 20 = (A + B)x + (2A - 10B)

Now;  we have to relate like terms on both sides; we have:

A + B = 1   ;   2A - 10 B = 20

By solvong the expressions above; we have:

A = \dfrac{5}{2}     B =  \dfrac{3}{2}

Now;

\dfrac{x+20}{(x-10)(x+2)} = \dfrac{5}{2(x-10)} + \dfrac{3}{2(x+2)}

Thus;

\dfrac{2x^3-16x^2-39x+20}{x^2-8x-20}= 2x + \dfrac{5}{2(x-10)}+ \dfrac{3}{2(x+2)}

Now; the integral is:

\int \dfrac{2x^3-16x^2-39x+20}{x^2-8x-20} \ dx =  \int \begin {bmatrix} 2x + \dfrac{5}{2(x-10)}+ \dfrac{3}{2(x+2)} \end {bmatrix} \ dx

\mathbf{\int \dfrac{2x^3-16x^2-39x+20}{x^2-8x-20} \ dx =  x^2 + \dfrac{5}{2}In | x-10|\dfrac{3}{2} In |x+2|+C}

3. Due to the fact that the maximum words this text box can contain are 5000 words, we decided to write the solution for question 3 and upload it in an image format.

Please check to the attached image below for the solution to question number 3.

4 0
3 years ago
Solve it :<br> 4xy2+5x+6xy2−2y2<br><br> pls finish this fast
photoshop1234 [79]

Answer:

20xy + 5x -4y

Step-by-step explanation:

I hope this helps you

6 0
3 years ago
Is 7.787887888... a rational number?
Ugo [173]

Answer:

I'm 75% sure that the answer is A, but not a 100. You might want to wait until you get more answers.

5 0
3 years ago
Read 2 more answers
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