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drek231 [11]
2 years ago
6

What is the range of the box plot shown? Select one: 104, 16, 99, 7

Mathematics
2 answers:
ikadub [295]2 years ago
6 0
Your range would be 97 for those numbers provided. You can find out the range by getting the biggest value number and subtracting it from the smallest value number . in this case you would do 104-7 which gives you 97 which would be your range
masha68 [24]2 years ago
3 0

Answer:  104,

16,

99,

7

Step-by-step explanation:

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May someone please help I am struggling bad
SVETLANKA909090 [29]

Answer:

5 12 9

Step-by-step explanation:

3 0
3 years ago
1. 112<br><br> 2. 136 <br><br> 3. 68 <br><br> 4. 158 <br><br> 5. 129
RideAnS [48]

Answer:

4. 158

Step-by-step explanation:

First let's make things a little simpler and put these arcs in terms of x.  We know that the degree measure around the outside of a circle, regardless of its size, is 360.  So let's say that arc BC is x.  That means that arc BDC is 360 - x.  This is because arc BC + arc BDC = 360.  Substituting in our x's we have:

x + 360 - x = 360 and

360 = 360.  (That's just the proof that putting in our x's as we did does in fact work!)

Following the formula then, we have

22=\frac{1}{2}(360-x-x) and

22=\frac{1}{2}(360-2x)

Multiply both sides by 2 to get rid of the fraction and get

44 = 360 - 2x

Subtract 360 rom both sides to get

-316 = -2x

Divide both sides by -2 to get that x = 158

Since we are looking for arc BC and we designated arc BC as our x, that means that arc BC = 158.

3 0
3 years ago
Secants L J and L M intersect and form an angle at point L. Solve for x.
german

Answer:

x = 14  

Step-by-step explanation:

Assume your diagram is like the one below.

The intersecting secant angles theorem states, "When two secants intersect outside a circle, the measure of the angle formed is one-half the difference between the far and the near arcs."

For your diagram, that means

\begin{array}{rcl}m\angle L &=&\dfrac{1}{2} \left(m \widehat {JM} - m\widehat {PQ}\right)\\\\(3x + 13)^{\circ}& = &\dfrac{1}{2} \left[(8x + 48)^{\circ} - (5x - 20)^{\circ}\right]\\\\3x + 13& = &\dfrac{1}{2}(8x + 48 - 5x + 20)\\\\3x + 13& = &\dfrac{1}{2}(3x + 68)\\\\6x + 26 & = & 3x + 68\\6x & = & 3x + 42\\3x & = & 42\\x & = & \mathbf{14}\\\end{array}

Check:

\begin{array}{rcl}(3\times14 + 13) & = &\dfrac{1}{2} \left[(8\times14 + 48)^{\circ} - (5\times14 - 20)^{\circ}\right]\\\\42 + 13& = &\dfrac{1}{2}(112 + 48 - 70 + 20)\\\\55& = &\dfrac{1}{2}(110)\\\\55 & = & 55\\\end{array}

It checks.

6 0
3 years ago
5/4 miness 5/8what does it equal ​
Ivan
Answer:
5/8
explanation:
5/4(2)=10/8-5/8
4 0
3 years ago
Please help me <br> I’ll mark brainiest
Lubov Fominskaja [6]

Answer:

which number

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8 0
2 years ago
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