Answer:
5 12 9
Step-by-step explanation:
Answer:
4. 158
Step-by-step explanation:
First let's make things a little simpler and put these arcs in terms of x. We know that the degree measure around the outside of a circle, regardless of its size, is 360. So let's say that arc BC is x. That means that arc BDC is 360 - x. This is because arc BC + arc BDC = 360. Substituting in our x's we have:
x + 360 - x = 360 and
360 = 360. (That's just the proof that putting in our x's as we did does in fact work!)
Following the formula then, we have
and

Multiply both sides by 2 to get rid of the fraction and get
44 = 360 - 2x
Subtract 360 rom both sides to get
-316 = -2x
Divide both sides by -2 to get that x = 158
Since we are looking for arc BC and we designated arc BC as our x, that means that arc BC = 158.
Answer:
x = 14
Step-by-step explanation:
Assume your diagram is like the one below.
The intersecting secant angles theorem states, "When two secants intersect outside a circle, the measure of the angle formed is one-half the difference between the far and the near arcs."
For your diagram, that means
![\begin{array}{rcl}m\angle L &=&\dfrac{1}{2} \left(m \widehat {JM} - m\widehat {PQ}\right)\\\\(3x + 13)^{\circ}& = &\dfrac{1}{2} \left[(8x + 48)^{\circ} - (5x - 20)^{\circ}\right]\\\\3x + 13& = &\dfrac{1}{2}(8x + 48 - 5x + 20)\\\\3x + 13& = &\dfrac{1}{2}(3x + 68)\\\\6x + 26 & = & 3x + 68\\6x & = & 3x + 42\\3x & = & 42\\x & = & \mathbf{14}\\\end{array}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Brcl%7Dm%5Cangle%20L%20%26%3D%26%5Cdfrac%7B1%7D%7B2%7D%20%5Cleft%28m%20%5Cwidehat%20%7BJM%7D%20-%20m%5Cwidehat%20%7BPQ%7D%5Cright%29%5C%5C%5C%5C%283x%20%2B%2013%29%5E%7B%5Ccirc%7D%26%20%3D%20%26%5Cdfrac%7B1%7D%7B2%7D%20%5Cleft%5B%288x%20%2B%2048%29%5E%7B%5Ccirc%7D%20-%20%285x%20-%2020%29%5E%7B%5Ccirc%7D%5Cright%5D%5C%5C%5C%5C3x%20%2B%2013%26%20%3D%20%26%5Cdfrac%7B1%7D%7B2%7D%288x%20%2B%2048%20-%205x%20%2B%2020%29%5C%5C%5C%5C3x%20%2B%2013%26%20%3D%20%26%5Cdfrac%7B1%7D%7B2%7D%283x%20%2B%2068%29%5C%5C%5C%5C6x%20%2B%2026%20%26%20%3D%20%26%203x%20%2B%2068%5C%5C6x%20%26%20%3D%20%26%203x%20%2B%2042%5C%5C3x%20%26%20%3D%20%26%2042%5C%5Cx%20%26%20%3D%20%26%20%5Cmathbf%7B14%7D%5C%5C%5Cend%7Barray%7D)
Check:
![\begin{array}{rcl}(3\times14 + 13) & = &\dfrac{1}{2} \left[(8\times14 + 48)^{\circ} - (5\times14 - 20)^{\circ}\right]\\\\42 + 13& = &\dfrac{1}{2}(112 + 48 - 70 + 20)\\\\55& = &\dfrac{1}{2}(110)\\\\55 & = & 55\\\end{array}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Brcl%7D%283%5Ctimes14%20%2B%2013%29%20%26%20%3D%20%26%5Cdfrac%7B1%7D%7B2%7D%20%5Cleft%5B%288%5Ctimes14%20%2B%2048%29%5E%7B%5Ccirc%7D%20-%20%285%5Ctimes14%20-%2020%29%5E%7B%5Ccirc%7D%5Cright%5D%5C%5C%5C%5C42%20%2B%2013%26%20%3D%20%26%5Cdfrac%7B1%7D%7B2%7D%28112%20%2B%2048%20-%2070%20%2B%2020%29%5C%5C%5C%5C55%26%20%3D%20%26%5Cdfrac%7B1%7D%7B2%7D%28110%29%5C%5C%5C%5C55%20%26%20%3D%20%26%2055%5C%5C%5Cend%7Barray%7D)
It checks.
Answer:
5/8
explanation:
5/4(2)=10/8-5/8