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Ivanshal [37]
3 years ago
13

Write an equation for the line below​

Mathematics
1 answer:
Stells [14]3 years ago
3 0
The answer is : y = -3x + 1
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5(1÷6) answers is what
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Three of the four vertices of a rectangle are located at (4, 2), (7, 2) and (4, 8). a. What are the coordinates of the missing v
34kurt

Answer:

a) The coordinates of the missing vertex = (7, 8)

b) Area = 18 square units

   Perimeter = 18 units

Step-by-step explanation:

a) We know three of the four vertices:

A: (4, 2)           C ______ D(?)

B: (7, 2)               |             |

C: (4, 8)           A |______| B  

To find the coordinates of the missing vertex we need to calculate the distance in the x-direction from point A to point B:

B_{x} - A_{x} = 7 - 4 = 3                    

Hence, the distance of point D from point C in the x-direction is:

D_{x} = C_{x} + 3 = 4 + 3 = 7

Now, to find the coordinate in "y" we need to calculate the distance in the y-direction between point C and point A:

C_{y} - A_{y} = 8 - 2 = 6  

Then, the distance of point D from point B in the y-direction is:

D_{y} = B_{y} + 6 = 2 + 6 = 8

Therefore, the coordinates of the missing vertex (point D) are:

D = (D_{x}, D_{y}) = (7, 8)    

b) The area of the rectangle is:

a = (B_{x} - A_{x})*(C_{y} - A_{y}) = 3*6 = 18 units^{2}

The perimeter is given by:

p = 2*(3 + 6) = 18 units

I hope it helps you!          

8 0
2 years ago
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3 years ago
Evaluate x(y-z)2 for =-1,y=5,and z=
Nata [24]

Answer:

The value of x(y-z)^2 is -16.

Step-by-step explanation:

We need to evaluate x(y-z)^2 for x = -1, y = 5 and let us assume that z = 1

It can be simply done by putting the values of x,y and z in the given expression.

x(y-z)^2=(-1)(5-1)^2\\\\=-1(4)^2

We know that the value of 4² = 16

So,

x(y-z)^2=16\times -1\\\\=-16

So, the value of x(y-z)^2 is -16.

6 0
3 years ago
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