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cupoosta [38]
4 years ago
7

Solve the inequality: |6x + 7| ≥ −3 and write the solution in interval notation

Mathematics
1 answer:
Mama L [17]4 years ago
8 0
Hello : 
<span> |6x + 7| ≥ −3 is right (true) for all reals : x because   </span><span> |6x + 7| ≥ 0 
</span><span>the set solution is : R 
</span>in interval notation : ]-∞,+∞[
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4 packages of gum in 8 weeks

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k ≥2

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A web-based company has a goal of processing 95 percent of its orders on the same day they are received. If 485 out of the next
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Answer:

The null hypothesis was rejected.

Conclusion: The proportions of orders completed on the day of receiving is more than 95%.

Step-by-step explanation:

The hypothesis can be defined as:

<em>H₀</em>: The proportions of orders completed on the day of receiving is not more than 95%, i.e. <em>p</em> ≤ 0.95.

<em>Hₐ</em>: The proportions of orders completed on the day of receiving is more than 95%, i.e. <em>p</em> > 0.95.

The significance level of the test is <em>α</em> = 0.025.

The sample size is, <em>n</em> = 500.

As the sample size is large, the sampling distribution of sample proportion can be approximated by the Normal distribution.

The mean and standard deviation of this distribution are:

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The test statistic is:

z=\frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n}} }

The sample proportion is:

\hat p=\frac{X}{n}=\frac{485}{500}=0.97

Compute the test statistic as follows:

z=\frac{0.97-0.95}{\sqrt{\frac{0.95(1-0.95)}{500}} }=2.05

The decision rule is:

If the <em>p</em>-value is less than the significance level <em>α</em> then the null hypothesis is rejected.

Compute the <em>p</em>-value as follows:

p-value=P(Z>2.05)\\=1-P(Z

*Use a <em>z</em>-table.

The <em>p</em>-value = 0.0202 < <em>α</em> = 0.025.

The null hypothesis will be rejected.

<u>Conclusion</u>:

As the null hypothesis was rejected at 2.5% level of significance, it can be concluded that the proportions of orders completed on the day of receiving is more than 95%.

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3 years ago
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