Answer:
Answer:So the maximum value of P is 138.Step-by-step explanation:
P(0,0)= 24(0) + 30(0) =0
P(0,1)= 24(0) + 30(1) =30
P(5,0)= 24(5) + 30(0) =120
P(2,3) =24(2) + 30(3) = 138I also
Answer:
y = 12
Step-by-step explanation:
∵ m∠ABC = 40
∵ BD ray is the bisector of ∠ABC
∴ m∠ABD = m∠CBD = 20
In 2 Δ BAD and BCD:
∵ m∠BAD = m∠BCD = 90°
∵ m∠ABD = m∠CBD = 20°
∵ BD is a common side in the two triangles
∴ ΔABD congruent to ΔCBD⇒(AAS)
∴ AD = CD
∴ 3y + 6 = 5y - 18
∴ 5y - 3y = 6 + 18
∴ 2y = 24
∴ y = 24/2 = 12
27 peices i believe. 3 peices per yard, 9 yards. 9*3=27
Answer:
-0.25
Step-by-step explanation:
Answer:
Step-by-step explanation:
we know that
The formula to calculate the depreciated value is equal to
where
V is the depreciated value
P is the original value
r is the rate of depreciation in decimal
x is Number of Time Periods
in this problem we have
substitute the values and solve for x
Apply log both sides
