What is the equation in slope-intercept form of the line that passes through the points (-4 , 6) and (12 , 2)?
2 answers:
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Answer:
Function <u>#2</u> has a greater minimum.
#3 < #1 < #2
Step-by-step explanation:
In the picture attached, the question is shown.
The minimum of Function #1 is located at (3, -1). This is seen in the picture.
The minimum of Function #2 is located at (1.5, 1). We can see in the table that the function is symmetric respect 1.5 (half-point between 1 and 2).
The function y = x² + 3x - 4 has its minimum at its vertex:
x-coordinate of vertex: x = -b/(2a) = -3/(2*1) = -1.5
y-coordinate of vertex: y = (-1.5)² + 3(-1.5) - 4 = -6.25
So, the minimum of Function #3 is located at (-1.5, -6.25)
