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kupik [55]
3 years ago
15

What is the equation in slope-intercept form of the line that passes through the points (-4 , 6) and (12 , 2)?

Mathematics
2 answers:
AVprozaik [17]3 years ago
8 0
Y = 8x + 8, I believe
lutik1710 [3]3 years ago
5 0

Answer:

I believe the answer is 4/16 or 2/8 simplified.

Step-by-step explanation:

you subtract y2-y1 and x2-x1 and divide the answers you get equaling 4/16.

You might be interested in
Problem page the sum of two numbers is 67 and the difference is 11 . what are the numbers?
pav-90 [236]
Try this:
1. sum of numbers is x+y=67, the difference between them is x-y=11
2. it is possible to make up and resolve the system:
\left \{ {{x+y=67} \atop {x-y=11}} \right. \ =\ \textgreater \  \  \left \{ {{x=39} \atop {y=28}} \right.
8 0
3 years ago
Which statement explains how the lines x + y = 2 and y = x + 4 are related?
zysi [14]
Answer: X = -1 and Y = 3
—————————————
X + Y = 2
X = 2 - Y
————————
Y = x + 4
Y = 2 - Y + 4
2Y = 2 + 4
2Y = 6
Y = 3
————————
X + Y = 2
X + 3 = 2
X = -1
8 0
2 years ago
Whats the slope for this question?
Nastasia [14]

Answer:

Slope:  1

Step-by-step explanation:

A variable is always worth 1 if there is no number in front of it. In this case there is no number, so just draw in a one.

6 0
2 years ago
Read 2 more answers
Helppppppp pleaseee
Viktor [21]

Answer:

x=2\sqrt{5}

Step-by-step explanation:

If that is a square, then all sides are the same. Therefore, it's a \sqrt{10} by \sqrt{10} shape. We'll use Pythagorean Theorem to find the diagonal.

a^2+b^2=c^2\\\sqrt{10}^2+ \sqrt{10}^2=x^2\\10+10=x^2\\20=x^2\\\sqrt{20}=x\\\sqrt{4*5}=x\\ 2\sqrt{5}=x

Since it's not a fraction, there is no denominator to rationalize. Let me know if you have any other questions!

5 0
2 years ago
Find the equation of the tangent line at the point (1, 6). for y = 4 + 4x2 - 2x3.
Lostsunrise [7]
y = 4 + 4 x^{2}-2x^{3}  Lets \ write \ it \ y = -2 x^{3} +4 x^{2} +4

The tangential line at a certain point is just the derivative so.
y ' = -6 x^{2} +8x. At the point (1,6) we plug the x value in and get the slope at the point (y ' = 2)

The tangential line at that point is
y - 6 = 2(x - 1)     (this is the answer)

6 0
3 years ago
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