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Alex17521 [72]
3 years ago
7

What is the value of x

Mathematics
1 answer:
geniusboy [140]3 years ago
6 0

Answer:

11

Step-by-step explanation:

3x+2

3(11)+2

33+2

35

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A certain club has 10 members, including Harry. One of the 10 members is to be chosen at random to be the president, one of the
devlian [24]

Answer:

The probability that Harry will be chosen as either as Secretary or as treasurer but not as president out of those 10 members will be \frac{1}{5}.

Step-by-step explanation:

We have 10 members out of which one is Harry, we need to choose one of the 10 members as President, one to be as secretary out of the remaining 9, one  as the treasurer of the remaining 8 members.

We want harry to be as either as secretary or as treasurer. so we will consider both the cases

Probability is given by = No of favorable outcomes/ Total no of outcomes

(1) Harry as secretary : If harry is to be chosen as secretary then he can't be a president or he cant be a Treasurer

  As president = \frac{1}{10}

  Not as president = 1 - \frac{1}{10} = \frac{9}{10}

Now he is selected for the secretary so he can't be selected as treasurer.

Not as treasurer = 1

Probability for chosen as secretary = \frac{9}{10}*\frac{1}{9}*1  = \frac{1}{10}  

(2) Harry as treasurer : If harry is to be chosen as the treasurer so he can't be chosen as a President or as a Secretary.

Probability for not chosen as president = \frac{9}{10}

Probability for not chosen as secretary =  1-\frac{1}{9} = \frac{8}{9}

Probability to be chosen as treasurer = \frac{1}{8}

Probability to be chosen as Treasurer = \frac{9}{10}*\frac{8}{9}*\frac{1}{8} = \frac{1}{10}

Total probability for Harry to be chosen as either secretary or as treasurer will be = P(Secretary) +P(Treasurer)

           = \frac{1}{10} +\frac{1}{10}  = \frac{1}{5}

Therefore the probability that Harry will be chosen as either as Secretary or as treasurer but not as president out of those 10 members will be \frac{1}{5}.

7 0
3 years ago
What is the frequency heard by a person driving at 15 m/s toward a blowing factory whistle (800. Hz) if the speed of sound is 34
bija089 [108]

Answer:

Answer:

835.29 Hz

Explanation:

When moving towards the source of sound, frequency will be given by

f*=f(vd+v)/v

Where f is the freqiency of the source, vd is the driving speed, v is the speed of sound in air, f* is the inkown frequency when moving forward.

Substituting 800 Hz for f, 340 m/s for v and 15 m/s for vd then

f*=800(15+340)/340=835.29411764704 Hz

Rounded off, the frequency is approximately 835.29 Hz

ı hope ıts true

Step-by-step explanation:

5 0
3 years ago
Cans 6 cm 3 cm and 9 cm make a triangle
Alja [10]

Answer:

Step-by-step explanation:

No it’s makes more than it so no

3 0
3 years ago
Read 2 more answers
Solve for x. Assume that lines which appear tangent are tangent. Help!!!
Serjik [45]

Answer:

x = 0

Step-by-step explanation:

From the intersecting secants theorem, If from an exterior point, we draw two secant segments to a circle, then the product of the length of one secant segment and its external secant part will be equal to the product of the length of the other secant segment and its external secant portion.

Thus, applying it to this question;

(x + 27 + 48) × (x + 27) = (x + 45)²

(x + 75)(x + 27) = x² + 90x + 2025

x² + 102x + 2025 = x² + 90x + 2025

Like terms will cancel put to give;

102x - 90x = 0

12x = 0

x = 0/12

x = 0

5 0
3 years ago
Use a system of equations to solve this problem. Dr. Graham currently has two acid solutions. She only has a 60% acid solution a
Natalka [10]
<span>Dr. Graham currently has two acid solutions.
60% acid AND 20% acid </span>
Dr. Graham needs 30 L of a 50% acid solution
We set up 2 equations in which s = 60% acid and t = 20% acid
A) s + t = 30
B) .60s + .20t = (.50 * 30)
We multiply equation A by -.20
A) = -.20s -.20t = -6 then we add it to B)
B) .60s + .20t = 15
.40s = 9
s = 22.5
t = 7.5
So, she needs to mix 22.5 liters of 60% acid with 7.5 liters of 20% acid.

Source:
http://1728.org/mixture.htm


4 0
3 years ago
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