If two sides of a triangle are 7 and 14, the third side may be?

Which figure must be a square?

Maslowich

I think the answer is A

Hope it helps :-)

7 0

4 years ago

Hey guys I don’t understand this one so can y’all please help me? :))))

aksik [14]

Answer:

11) c = 16.1

12) c = 11.4

Step-by-step explanation:

11)

a² + b² = c²

8² + 14² = c²

64 + 196 = c²

c² = 260

$\sqrt{c^2} =\sqrt{260}$

c = 16.1

12)

a² + b² = c²

7² + 9² = c²

49 + 81 = c²

c² = 130

$\sqrt{c^2} =\sqrt{130}$

c = 11.4

6 0

3 years ago

Read 2 more answers

Please help me

Aleksandr [31]

Answer:

x=1

Step-by-step explanation:

-8x+2(4+2)=4

-8x+2×6=4

-8x+12=4

-8x=4-12

-8x= -8

we multiply both sides with (-1) to get a positive number in the x side

-8x= -8 / ×(-1)

8x=8

x=8/8

x=1

5 0

2 years ago

Read 2 more answers

Last June only 0.17 inches of rain fell all month. What is the difference between the average rainfall and the actual rainfall f

spin [16.1K]

Answer:

Part 1) 0.50 inches

Part 2) 1.14 inches

Part 3)

a) 1.25 inches

b) -0.32 inches

Step-by-step explanation:

The complete question in the attached figure

Part 1) Last June only 0.17 inches of rain fell all month. What is the difference between the average rainfall and the actual rainfall for the last June

Let

x ----> the average rainfall for the last June

y ----> the actual rainfall for the last June

The difference between the average rainfall and the actual rainfall for the last June is given by the expression

$(x-y)$

we have

$x=0.67\ in\\y=0.17\ in$

substitute

$0.67-0.17=0.50\ in$

Part 2) The departure from the average rainfall last July was -0.36 inches. How much rain fell last July?

we know that

The departure from the average is the difference between the actual amount of rain and the average amount of rain for a given month

Let

D -----> the departure from the average

x ----> the average rainfall for the last June

y ----> the actual rainfall for the last June

so

$D=y-x$

we have

$D=-0.36\ in\\x=1.5\ in$

substitute the given values

$-0.36=y-1.5$

solve for y

$y=1.5-0.36\\y=1.14\ in$

Part 3)

<u>Part a)</u> How much rain would have to fall in August so that the total amount of rain equals the average rainfall for these three months?

<u>Part b</u>) What would the departure from the average be in August in that

situation?

Part a) How much rain would have to fall in August so that the total amount of rain equals the average rainfall for these three months?

Find the average rainfall for these three months

Adds the average rainfall and divide by 3

$(0.67+1.5+1.57)/3=1.25\ in$

Part b) What would the departure from the average be in August in that

situation?

we know that

The departure from the average is the difference between the actual amount of rain and the average amount of rain for a given month

Let

D -----> the departure from the average

x ----> the average rainfall for the last June

y ----> the actual rainfall for the last June

so

$D=y-x$

we have

$x=1.57\ in\\y=1.25\ in$

substitute the given values

$D=1.25-1.57=-0.32\ in$

7 0

4 years ago

EFG is an isosceles triangle in E such that EF = EG = 6cm and FG = 5cm. The circle (C) with center O and diameter [EG] intersect

SVEN [57.7K]

Answer:

Calcium carbonate reacts w/stomach acid according to the following chemical equation.

CaCO3+2HCl(aq)-> CaCl2(aq)+H2O(l)+CO2(g)

8 0

3 years ago