Answer:
the area will be increased by 44%
Step-by-step explanation:
We are given the following variables:
μ = the sample mean = 152 pounds
σ = the standard deviation = 26 pounds
x = the sample value we want to test = 180 pounds
n = the sample size = unknown
MOE = margin of error = 4% = 0.04
Confidence level = 96%
The first thing we can do is to find for the value of z
using the formula:
z = (x – μ) / σ
z = (180 – 152) / 26
z = 1.0769 = 1.08
Since we are looking for the people who weigh more than
180 pounds, therefore this is a right tailed z test. The p value is:
p = 0.1401
Then we can use the formula below to solve for n:
n = z^2 * p * (1 – p) / (MOE)^2
n = 1.08^2 * 0.1401 * (1 – 0.1401) / (0.04)^2
n = 87.82 = 88
Therefore around 88 people must be surveyed.
Answer:
The function is:
y = 150*x
where y is the number of calories consumed, and x is the number of pieces of candy consumed.
Now, the domain of a function is the possible values of x that you can input in the function.
For this particular case you can have:
x = 0 (no pieces candy)
x = 1 (one piece of candy)
x = 2 (two pieces of candy)
Notice that x can be only whole numbers because, in principle, you can't eat a fraction of a piece of candy.
So we only use x = whole numbers.
Then the domain of the function is equal to all the natural numbers plus the zero, or:
D = {x ∈ N ∪ {0}}
"x belongs to the union between the set of the natural numbers and the zero"
Step-by-step explanation:
Answer: Consider the equation
Taking square root on both the sides of the equation, we get
Consider
adding '1' to both sides, we get
Dividing by '3', we get
Consider
adding '1' to both sides, we get
Dividing by '3', we get
So, the solution set for this equation is and .
Question 2:
Consider the equation
We will use quadratic formula, we get
So, the solution set for this equation is .
Question 3:
Consider the equation
By using the quadratic formula, we get
so, the solution set for this equation is .
Step-by-step explanation:
Hope this helps! Arc CE should be 80.