Question

Hey guys I don’t understand this one so can y’all please help me? :))))

Answer 1

Answer:

11) c = 16.1

12) c = 11.4

Step-by-step explanation:

11)

a² + b² = c²

8² + 14² = c²

64 + 196 = c²

c² = 260

$\sqrt{c^2} =\sqrt{260}$

c = 16.1

12)

a² + b² = c²

7² + 9² = c²

49 + 81 = c²

c² = 130

$\sqrt{c^2} =\sqrt{130}$

c = 11.4

Answer 2

• Question 1 :-

We see that in a right angled triangle two sides are 8cm and 14cm . We can find the third side using Pythagoras Theorem .

$\tt \to Hypotenuse^2 = Perpendicular^2+Base^2\\\\\tt \to h^2 = (8)^2+(14) \\\\\to \tt h^2 = 64 + 196 \\\\\tt \to h^2 = 260 \\\\\tt \to h=\sqrt{260} \\\\\tt \to \boxed{\orange{\tt h = 16.12 }}$

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• Question 2 :-

$\tt \to Hypotenuse^2 = Perpendicular^2+Base^2\\\\\tt \to h^2 = (9)^2+(7)^2 \\\\\to\tt h^2 = 81 + 49 \\\\\tt \to h^2 = 130 \\\\\tt \to h=\sqrt{130} \\\\\tt \to \boxed{\orange{\tt h = 11.40}}$