For the graph below, what should the domain be so that the function is at least 600? (1 point)
1 answer:
Answer: The first interval:0 ≤ x ≤ 20
Procedure
You have to solve this inequality
-2x^2 +40x +600 ≥ 600
-2x^2 +40x ≥ 0
-x^2+20x ≥ 0
x^2 - 20 x ≤ 0
x(x-20) ≤ 0
That is only possible if the two factors have different signs.
Let's examine the possibilities
x ≥ 0 and x -20 ≤ 0⇔x≤20, that is 0≤x≤20
The other possibility is
x ≤ 0 and x - 20 ≥ 0 ⇔x≥20. This conditions is not possible.
So the solution is 0≤x≤20
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1= 5/4
2= -103/40
1st explanation
-12/15 + 4/5 + 7/12
-8 + 48 + 35/60
75/60
5/4
2nd explanation
-1 3/5 + 5 1/8 - 6 1/10
-8/5 + 41/8 + 61/10
- 64 + 205 + 244 / 40
-103/140
-103 / 40
Answer:
A. Domain: (-1, 3, 5)
Step-by-step explanation:
The domain is always the x-inputs or x-values of a function.
Answer:
57% of students
Step-by-step explanation:
14 + 29 = 43%
100% - 43% = 57%
Lets get these into improper fractions.
1*8 + 5 = 8+5 = 13
13/8
1*3 + 2 = 3+2 = 5
5/3
Now divide
13/8 = 1.625
5/3 = 1.6666
1 2/3 is larger
Answer:
x = -2
Step-by-step explanation:
x^2 + 4x + 4 = 0
quadratic formula:
-b +or- sqrt(b^2-4ac)/2a
-4 +/- sqrt ((-4)^2-4*1*4)/2*1
-4+/- sqrt(16-16) / 2
-4 +/- 0 / 2
-4/2
-2