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Sonja [21]
3 years ago
12

What is the solution of x^2+x-6≤0?

Mathematics
1 answer:
mr_godi [17]3 years ago
8 0
1) Factor the polynomial

x^2 + x - 6 = (x + 3) (x - 2)

So, can solve (x + 3)(x - 2) ≤ 0

The condition for the product of two factors be zero or negative is that the both are zero or have different signs (one positive and the other negative)

a) when x + 3 ≤ 0 and x - 2 ≥ 0

x + 3 ≤ 0 => x ≤ - 3

x - 2 ≥ 0 => x ≥ 2

Given that it is imposible that x be less or equal tha - 3 and greaer or  equal than 2, this solution is empy.

b) when x + 3 ≥ 0 and x - 2 ≤ 0

x + 3 ≥ 0 => x ≥ - 3

x - 2 ≤ 0 => x ≤ 2

Solution: - 3 ≤ x ≤ 2 or [-3,2]
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(c-a, 0)

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The slope-intercept formula for the equation of a straight line is the most convenient to use here, since we can tell immediately from the graph that the y-intercept is (0, -3):

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Read 2 more answers
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