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Sonja [21]
3 years ago
12

What is the solution of x^2+x-6≤0?

Mathematics
1 answer:
mr_godi [17]3 years ago
8 0
1) Factor the polynomial

x^2 + x - 6 = (x + 3) (x - 2)

So, can solve (x + 3)(x - 2) ≤ 0

The condition for the product of two factors be zero or negative is that the both are zero or have different signs (one positive and the other negative)

a) when x + 3 ≤ 0 and x - 2 ≥ 0

x + 3 ≤ 0 => x ≤ - 3

x - 2 ≥ 0 => x ≥ 2

Given that it is imposible that x be less or equal tha - 3 and greaer or  equal than 2, this solution is empy.

b) when x + 3 ≥ 0 and x - 2 ≤ 0

x + 3 ≥ 0 => x ≥ - 3

x - 2 ≤ 0 => x ≤ 2

Solution: - 3 ≤ x ≤ 2 or [-3,2]
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1. 7

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Step-by-step explanation:

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3 years ago
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Answer:

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Step-by-step explanation:

Area of a rectangle = (length)(width).

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W = ------------------------------

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If the width, W, is 15, then the length is 4 less, or L = 11.

The dimensions are 11 cm by 15 cm

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The second is at x=3 and y=0

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