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postnew [5]
2 years ago
15

Can a rhombus be a kite? If so explain. Is every quadrilateral a parallelogram? If so explain.

Mathematics
1 answer:
Lena [83]2 years ago
7 0
No, a rhombus cannot be a kite because kites have very specific angles and shapes that have to be present in order for the shape to be classified as a kite.
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GUYS I NEED HELP PLSSSSSS! Ive been working on this ALL day!
Vika [28.1K]

First, let's write what we know.

We can represent the number of students in the play from each class as L, G, and C. We know that L = 7, and if Gardener has 4 more students than Cho, then G = C + 4.

Then, taking the third line, we can write an inequality:

C < L < G

C < 7 < C + 4

C - 4 < 3 < C

3 < C < 7

If C is greater than 3 and less than 7 and is an integer, than means C is 4, 5, or 6.

Then, we need to find how many students are in the play.

C + L + G

C + 7 + C + 4

2C + 11

So we have our expression for the number of students in the play. Then, we need to find the total number of students. We know that 2C + 11 will be 30% of the total, so if T is the total, we can find T.

0.3T = 2C + 11

(Divide by 3/10 or multiply by 10/3 on both sides)

T = 20/3 C + 110/3

We know from before that C is 4, 5 or 6. We can plug these into our equation here to find which one produces a whole number.

T = 20/3 * 4 + 110/3

T = 190/3

T = 20/3 * 5 + 110/3

T = 210/3

T = 70

T = 20/3 * 6 + 110/3

T = 230/3

We can see here that only when C is 5 will the total be a whole number. That means Mrs. Cho has 5 students in the play. If Mrs. Gardner has 4 more than that, she has 9 students in the play in her class.  We now need to figure out the number of student in her class.

The total students are Cho's, Logan's, and Gardner's classes added together. We know that Logan's class is 23 students, so if we subtract that from the total, we can see that Cho's and Gardner's class have 47 students. If Mrs. Cho has 24 students in her class, we can subtract that from the 47, so we know that Mrs. Gardner has 23 students in her class.

4 0
3 years ago
A statistics textbook chapter contains 60 exercises, 6 of which are essay questions. A student is assigned 10 problems. (a) What
Scilla [17]

Answer:

a) P=0.3174

b) P=0.4232

c) P=0.2594

d) The shape of the hypergeometric, in this case, is like a binomial with mean np=1.

Step-by-step explanation:

The appropiate distribution to model this is the hypergeometric distribution:

P(X=x)=\frac{\binom{s}{x}\binom{N-s}{M-x}}{\binom{N}{M}}=\frac{\binom{6}{x}\binom{54}{10-x}}{\binom{60}{10}}

a) What is the probability that none of the questions are essay?

P(X=0)=\frac{\binom{6}{0}\binom{54}{10-0}}{\binom{60}{10}}\\\\P(X=0)=\frac{1*(54!/(10!*44!)}{60!/(10!*50!)} =\frac{2.3931*10^{10}}{7.5394*10^{10}} = 0.3174

b)  What is the probability that at least one is essay?

P(X=1)=\frac{\binom{6}{1}\binom{54}{9}}{\binom{60}{10}}\\\\P(X=1)=\frac{6*(54!/(9!*43!)}{60!/(10!*50!)} =\frac{3.1908*10^{10}}{7.5394*10^{10}} =0.4232

c) What is the probability that two or more are essay?

P(X\geq2)=1-(P(0)+P(1))=1-(0.3174+0.4232)=1-0.7406=0.2594

8 0
3 years ago
Pls help...also ill mark brainlest
pentagon [3]

Answer:

D

Step-by-step explanation:

I think it is D

4 0
2 years ago
How many feet are in 100meters
77julia77 [94]

Answer: 328 feet, 1 inch

Step-by-step explanation:

3.281 feet makes 1 meter

To solve the question, Multiply the value by 3.281:

100 meters = 100 x 3.281 feets

=328.1 feet

I hope this helps.

5 0
2 years ago
F(x)= (x+2)^2 -1<br> Find x intercept <br> Find y intercept<br> Find vertex
Trava [24]
The x intercept occurs when y = 0.

0=(x+2)^2 - 1
1=(x+2)^2

Take the square root of both sides. Note that the sqrt of 1 is 1. Then solve for x.

1=x+2
-1=x

The x intercept is -1.

The y intercept occurs when x=0.

y=(0+2)^2 - 1
y=2^2 -1
y=4-1
y=3

The y intercept is 3.

Now, to find the vertex...

This parabola is currently in a format called the vertex form, which is:

f(x) = (x-h)^2 + k

where (h, k) is the vertex.

Therefore, the vertex is (-2, -1).
6 0
3 years ago
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