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nalin [4]
3 years ago
5

1 + 1. Help me please

Mathematics
1 answer:
sesenic [268]3 years ago
4 0

Answer:

depending on who u r, either 2 or 11

tysssssm 4 the points!!!!!  

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Simplify the following integer radical expression. <br> Show all work. <br> Square root of 24
cluponka [151]

Answer:

2 times the square root of 6

Step-by-step explanation:

square root of 24 is the same as square root of 4 times square root of 6, so you simplify the square root of 4 and you get 2, and you end with 2 time the square root of 6

3 0
3 years ago
Can you please help me?
ser-zykov [4K]

Answer:

idek

Step-by-step explanation:

srry

8 0
3 years ago
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An electrician charges $40 for each hour he works plus a $125 service charge. The total charge for a recent job was $1,205. Whic
maks197457 [2]

Answer:

Answer is D.

Step-by-step explanation:

40h is what you start out with since it costs 40 ever hour. then you add the service charge which makes it 40h + 125, and then since the total charge is 1205, that would complete the equation.

5 0
3 years ago
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What is the n in 4 1/2 = 1 1/2n; n =
jasenka [17]

Answer:

9/11

Step-by-step explanation:

4 1/2= 9/2=11/2n

so n =9/11

so 9/2=11/2*9/11

8 0
3 years ago
Which choice is equivalent to the expression below when y2 0?<br> √y^2 + √16y^3 – 4y√y
DanielleElmas [232]

Answer:

Option C.

Step-by-step explanation:

We start with the expression:

\sqrt{y^3}  + \sqrt{16*y^3} - 4*y\sqrt{y}

where y > 0. (this allow us to have y inside a square root, so we don't mess with complex numbers)

We want to find the equivalent expression to this one.

Here, we can do the next two simplifications:

\sqrt{16*y^3} = \sqrt{16} \sqrt{y^3} = 4*\sqrt{y^3}

And:

y*\sqrt{y} = \sqrt{y^2} *\sqrt{y} = \sqrt{y^2*y} = \sqrt{y^3}

If we apply these two to our initial expression, we can rewrite it as:

\sqrt{y^3}  + \sqrt{16*y^3} - 4*y\sqrt{y}

\sqrt{y^3}  + 4*\sqrt{y^3} - 4\sqrt{y^3} = \sqrt{y^3}

Here we can use the second simplification again, to rewrite:

\sqrt{y^3} = y*\sqrt{y}

So, concluding, we have:

\sqrt{y^3}  + \sqrt{16*y^3} - 4*y\sqrt{y} = y*\sqrt{y}

Then the correct option is C.

8 0
3 years ago
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