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bija089 [108]
3 years ago
14

Which of the following are solutions to the inequality -7x+14>-3x-6 ? Select all that apply

Mathematics
1 answer:
adoni [48]3 years ago
4 0
Since you didn't put the solutions I'll just explain how to answer it. Most likely the answers are in (x,y) form. Just substitute x and y into the equation and then solve. If it is true it is a solution. 

Example: 2x ≥ 4x - 2 
A. 1
2(1) ≥ 4(1) - 2
2 ≥ 4 - 2
2 ≥ 2 
In this instance A would be a correct answer.

(If you would like me to actually answer the question than you will need to include the answer choices.) 
You might be interested in
| x - 1 | = 5x + 10<br> Check for extraneous solutions.
Ronch [10]
[x-1]=5x+10

We have two equations:
1) x-1=5x+10

x-1=5x+10
x-5x=10+1
-4x=11
x=-11/4

2) x-1=-(5x+10)

x-1=-(5x+10)
x-1=-5x-10
x+5x=-10+1
6x=-9
x=-9/6=-3/2

we have two  possible solutions:
solution₁;       x=-11/4
solution₂:       x=-3/2

we check it out:
1) x=-11/4
[x-1]=5x+10
[-11/4  - 1]=5(-11/4)+10
[(-11-4)/4]=-55/4  + 10
[-15/4]=(-55+40) /4
15/4≠-15/4   This solution don´t work.

2) x=-3/2
[x-1]=5x+10
[-3/2  - 1]=5(-3/2)+10
[(-3-2)/2]=-15/2  + 10
[-5/2]=(-15+20)/2
5/2=5/2; this solution works.

Therefore:

Answer: x=-3/2.
8 0
3 years ago
Read 2 more answers
Suppose you obtain a 20-year mortgage loan of $194,000 at an annual interest rate of 7.8%. The annual property tax bill is $979
Katena32 [7]

Answer:

428.40

Step-by-step explanation:

done

5 0
3 years ago
Find the LCm for each set of numbers 32 128
allsm [11]
The LCM is of 128 and 32 is 128 
7 0
3 years ago
Read 2 more answers
Julie is using the set {7,8,9,10,12} to solve the inequality shown
d1i1m1o1n [39]

Answer hola senior me no espanol

Step-by-step explanation:

1+1=2?????? easy IT SO EASY!!!!!!!

3 0
2 years ago
A line passes through (0, –7) and has a slope of -2/3. What is the equation of the line in slope-intercept form
babunello [35]

Answer:

the required equation is y = ( -2/3 )x -7

Step-by-step explanation:

<u>Given</u><u> </u><u>:</u><u>-</u><u> </u>

<em> </em>

<em>the</em><em> line </em><em>passes </em><em>thr</em><em>ough</em><em> </em><em>the </em><em>point</em><em> ( </em><em>0</em><em> , -</em><em>7</em><em> </em><em>)</em>

<em>)and slope of the line is </em><em>(</em><em> </em><em>-</em><em>2</em><em>/</em><em>3</em><em> </em><em>)</em>

<em>• To form an equation when one point and it's slope is given , </em>

<em>• To form an equation when one point and it's slope is given , we use ;</em>

<em>• To form an equation when one point and it's slope is given , we use ;( y - y1 ) = m ( x - x1 )</em>

<em>• To form an equation when one point and it's slope is given , we use ;( y - y1 ) = m ( x - x1 )Where , x and y are variables</em>

<em>• To form an equation when one point and it's slope is given , we use ;( y - y1 ) = m ( x - x1 )Where , x and y are variablesand x1 and y1 are the points where the line meet ! </em>

<em>• To form an equation when one point and it's slope is given , we use ;( y - y1 ) = m ( x - x1 )Where , x and y are variablesand x1 and y1 are the points where the line meet ! and m is slope of the tangent !!</em>

<em>y1</em><em> </em><em>=</em><em> </em><em>-</em><em>7</em>

<em>x1</em><em> </em><em>=</em><em> </em><em>0</em>

<em>So, putting all the values in the equation we get ,</em>

<em>(y - ( - 7)) =  \frac{( -2 )}{3} (x - 0) \\  \\ y + 7 =  \frac{ - 2}{3} x \\  \\ 3y + 21 =  - 2x \\  \\ 3y =  - 2x - 21</em>

<em>3y =  - 21 - 2x \\  \\ y =   \frac{ - 2}{3} x -  \frac{21}{3  }  \\  \\ y =  \frac{ - 2}{3} x - 7</em>

<em>• Slope intercept form of the equation </em>

<em>• Slope intercept form of the equation y = mx + c </em>

<em>• Slope intercept form of the equation y = mx + c Where , m is slope of the line </em>

<em>• Slope intercept form of the equation y = mx + c Where , m is slope of the line and c is y intercept !! </em>

<em>[</em><em> </em><em>also</em><em> </em><em>,</em><em> </em><em>we</em><em> </em><em>can</em><em> </em><em>direc</em><em>tly</em><em> </em><em>put</em><em> </em><em>the</em><em> </em><em>value</em><em> </em><em>of</em><em> </em><em>c</em><em> </em><em>=</em><em> </em><em>-</em><em>7</em><em> </em><em>and</em><em> </em><em>m</em><em> </em><em>=</em><em> </em><em>(</em><em> </em><em>-</em><em>2</em><em>/</em><em>3</em><em> </em><em>)</em><em> </em><em>from</em><em> </em><em>given</em><em> </em><em>]</em>

<em>Hence , here m = </em><em>(</em><em>-</em><em>2</em><em>/</em><em>3</em><em> </em><em>)</em><em> and c = </em><em>-</em><em>7</em>

<em>So, the required equation is y = </em><em>(</em><em> </em><em>-</em><em>2</em><em>/</em><em>3</em><em> </em><em>)</em><em>x</em><em> </em><em>-</em><em>7</em>

5 0
3 years ago
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