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Zigmanuir [339]

3 years ago

11

Meg is a veterinarian. She found that 10 of the 59 dogs she saw this week were boxers. Steve is also a veterinarian. He found th

at 50% of the 4 dogs he saw this week were boxers . Does each person need to find the part, the whole. or the percent?

1 answer:

Finger [1]3 years ago

6 0

Answer:

Meg:percent Steve:part

Step-by-step explanation:

I got it right

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ZanzabumX [31]

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Luda [366]

Answer:

The 99% confidence interval is $71.67 < \mu < 78.33$

Step-by-step explanation:

From the question we are told that

The sample size is $n = 15$

The sample mean is $\= x = 75$

The standard deviation is $s = 5$

Given that confidence is 99% then the level of significance is mathematically represented as

$\alpha = 100 - 99$

$\alpha = 1\%$

$\alpha = 0.01$

Next we obtain the critical values of $\frac{ \alpha }{2}$ from the normal distribution table

The value is

$Z_{\frac{ \alpha }{2} } = 2.58$

Generally the margin for error is mathematically represented as

$E = Z_{\frac{ \alpha }{2} } * \frac{ s}{ \sqrt{n} }$

=> $E = 2.58 * \frac{ 5}{ \sqrt{15} }$

=> $E = 3.3307$

The 99% confidence interval is mathematically represented as

$\= x -E < \mu < \= x +E$

=> $75 - 3.3307 < \mu$

=> $71.67 < \mu < 78.33$

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The answer will ve
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