Ask question

Ask question

All categories

Zigmanuir [339]

3 years ago

11

Meg is a veterinarian. She found that 10 of the 59 dogs she saw this week were boxers. Steve is also a veterinarian. He found th

at 50% of the 4 dogs he saw this week were boxers . Does each person need to find the part, the whole. or the percent?

1 answer:

Finger [1]3 years ago

6 0

Answer:

Meg:percent Steve:part

Step-by-step explanation:

I got it right

You might be interested in

Sharonda is plotting quadrilateral PQRS on the graph below. She will plot the fourth and

lana [24]

Answer:

11 units

Step-by-step explanation:

Length of side PS can be calculated using the distance formula, $d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Where,

$P(-2, 5) = (x_1, y_1)$ (the coordinate of P is gotten from the graph)

$S(9, 5) = (x_2, y_2)$ (given)

$PS = \sqrt{(9 - (-2))^2 + (5 - 5)^2}$

$PS = \sqrt{(11)^2 + (0)^2}$

$PS = \sqrt{121} = 11 units$

3 0

4 years ago

What's 304÷9 with a remainder?

TiliK225 [7]

33.7777 this is the answer I got.

4 0

3 years ago

Read 2 more answers

Vertex (0,1) x intercepts is - 1 and 1 what is the equation of the parabola?

MrRa [10]

$\bf y=a(x-{{ h}})^2+{{ k}}\\
x=a(y-{{ k}})^2+{{ h}}\qquad\qquad vertex\ ({{ h}},{{ k}})$

those are the vertex form of a parabola... so hmmm
the vertex of this one is at 0,1 and intercepts or "solutions" are at -1 and 1, so is opening downwards, notice the picture below

that means, the squared variable is the "x", thus the form is $\bf y=a(x-{{ h}})^2+{{ k}}$

now, we know the vertex is at 0,1, and two x-intercepts of $\pm 1,0$

thus $\bf y=a(x-{{ h}})^2+{{ k}}\qquad 
\begin{cases}
h=0\\
k=1\\
when
\\
x=\pm 1\\
y=0
\end{cases}
\\\\\\
\textit{so.. hmmm let us use the point ... say hmmm 1,0}
\\\\
y=a(x-{{ h}})^2+{{ k}}\implies 0=a(1-0)^2+1$

solve for "a", to see what that coefficient is, then plug it back in the vertex form equation

6 0

3 years ago

How do you do 5ln x= 35....?

sergejj [24]

That's going to depend a lot on what you want to "do" to it.

I'm going to assume that you want to find a number for 'x' that makes
the whole equation a true statement. Here's how I would do it:

<u> 5 ln(x) = 35</u>

Divide each side by 5: ln(x) = 35/5
ln(x) = 7

Raise 'e' to the power of each side: e^[ ln(x) ] = e⁷

But e^[ ln(x) ] is just 'x'. So x = e⁷ = <em>1,096.633...</em> (rounded)

That's the only number you can write in place of 'x'
and make the original equation true.

5 0

3 years ago

10% of a number is 6, what is the number?

zaharov [31]

60 cos 10% of 60 is 6

3 0

3 years ago